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2 years ago

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Using the data below, what is the 3 period moving average forecast for the 4th week? week time series value 1 19.00 2 13.00 3 22

.00 4 19.00

1 answer:

Rufina [12.5K]2 years ago

5 0

(19 +13 +22)/3 = 18 . . . . . the forecast for week 4 is the average of weeks 1-3

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Classify each characteristic according to whether it is true for an amoeba, a clock, or both.

Stells [14]

Answer:

Amoeba is a single celled eukaryotic organism, found in the water body. These organisms have a false feet called as pseudopodium. It helps in the locomotion and captures food from the external environment. The organism does not exhibit a well defined shape. It has organelles like nucleus and vacuoles surrounded by cytoplasm. The food being captured by psuedopodium is engulfed inside a vacuole. It reproduces by the process of asexual reproduction called as binary fission. The genetic material replicates by the mitotic division, then the cell divides into two equal daughter cells. The amoeba obtains energy from food, and it uses this energy to move, capture food and reproduce.

A clock is a non-living thing. That displays time. It has three needles or hands, the bigger hand displays hour, the small one displays minutes and the thin needle displays seconds. These hands or needles uses energy from a cell or battery.

Characteristics features of amoeba are as follows:

Uses energy

Has internal organization

Characteristics features of clock are as follows:

Uses energy

Contains cells

Lacks genetic material reproduces

Has a defined boundary

Has internal organization

Step-by-step explanation:

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2 years ago

Read 2 more answers

In the derivation of the quadratic formula by completing the square, the equation (x+b over 2a)^2=-4ac+b^2 over 4a^2 is created

vredina [299]

Answer:

The result of applying the square root property of equality to this equation is $x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$ .

Step-by-step explanation:

Consider the provided equation.

$\left(x+\dfrac{b}{2a}\right)^2=\dfrac{-4ac+b^2}{4a^2}$

As the above equation is formed by perfect square trinomial so simply applying the square root property as shown:

$\sqrt{(x+\dfrac{b}{2a})^2}=\pm \dfrac{\sqrt{-4ac+b^2}}{\sqrt{4a^2}}\\x+\dfrac{b}{2a}=\pm \dfrac{\sqrt{b^2-4ac}}{2a}$

Isolate the variable x.

$x=-\dfrac{b}{2a}\pm \dfrac{\sqrt{b^2-4ac}}{2a}\\x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Hence, the result of applying the square root property of equality to this equation is $x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$ .

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2 years ago

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Study the steps used to solve the equation. Given: StartFraction c Over 2 EndFraction minus 5 equals 7 Step 1: StartFraction c O

Bas_tet [7]

Answer:

addition property of equality
integers are closed to addition
identity element
multiplication property of equality
commutative property of multiplication; reals are closed to multiplication; identity element

Step-by-step explanation:

<u>Given</u>:

c/2 -5 = 7

Step 1: c/2 -5 +5 = 7 +5

Step 2: c/2 +0 = 12

Step 3: c/2 = 12

Step 4: 2(c/2) = 12(2)

Step 5: c = 24

<u>Find</u>:

The property that justifies each step of the solution.

<u>Solution</u>:

Step 1: addition property of equality (lets you add the same to both sides)

Step 2: integers are closed to addition

Step 3: identity property of addition (adding 0 changes nothing)

Step 4: multiplication property of equality

Step 5: closure of real numbers to multiplication; identity property of multiplication

_____

It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.

In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.

Apart from the arithmetic, the other properties used are properties of equality. Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.

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2 years ago

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A pound of coffee beans yields 50 cups of coffee (4 cups = 1 qt). how many milliliters of coffee can be obtained from 2 g of cof

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You can have yourself 10 milliliters of coffee

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2 years ago

Erik's disabled sailboat is floating stationary 3 miles east and 2 miles north of Kingston. A ferry leaves Kingston heading towa

sergij07 [2.7K]

Answer:

Step-by-step explanation:

Let's suppose that Ballard is an origin with coordinates (0;0)

Ballard is 8 miles south and 1 mile west of Edmonds ⇒ Edmonds is 1 mile east and 8 miles north of Ballard.

Thus, coordinates of Edmonds (0+1; 0+8) (1;8)

Edmonds is 6 miles due east of Kingston. So, is 6 miles due of Edmonds

Thus, Kingston coordinates (1-6;8) (-5:8)

Sailboat is 3 miles east and 2 miles north of kingston

So, coordinates of sailboat are (-5+3; 8+2) (-2;10)

a)

Ferry leaves Kingston towards Edmonds at mph and Edmonds is 6 miles due east of Kingston.

Initial ferry coordinates as calculated above are equal to Kingston coordinates (-5;8)

After 20 minutes the ferry turns to south.

This distance travelled (20min) is d=9mph*20/60h=3 miles

So, ferry travelled 3 miles toward east in 20 min

Then, coordinates became (-5+3;8+0) (-2;8)

Thus, we have a line connecting two points (-5;8) and (-2;8)

Line connecting them has an equation:

y-8 = (8-8)/(-2+5) * (x+5)

y-8=0

y=8 - This is the equation for the first 20 minutes of travel

Then, ferry turns due south (-2;8) and has a vertiacl line

The equation of verical line is x=a, so the equation will be x=2

b) The sailboat has a radar scope that will detect any object within 3 miles of the sailboat.

region looks like a circular disc with a center (-2;10)

(x+2)^2+(y-10)^2=3^2

(x+2)^2+(y-10)^2 <9 (interior of the circular disc)

(x+2)^2+(y-10)^2 >9 (exterior)

The equation of the line joining the Kingston and Edmonds is y=8

the point of intersection:

(x+2)^2+(8-10)^2=9

(x+2)^2=5

x is approximately 0.24; -4.24

(0.24;8) (-4.24;8) - intersection points

c) The ferry exits the radar during the trid due south long x=-2

The points of intersection of the circle and the line x=-2:

(-2+2)^2+(y-10)^2=9

0+(y-10)^2=0

y is 7.13

(-2;7)

d) Takes south turn at (-2;8), then ferry travels 0.8 miles up to point (-2;7) where it exists the radar zone

Speed is 9mph

The time taken to cover 1 mile = t=1/9hr=1/9 *60=6.667min

So, it exists after 6.67 minutes

e) Ferry enters at (-4.24;8) and takes turn due to south at (-2;8)

The distance travelled is = [-4.24+2]=2.24 miles

The time taken to cover these miles is = t=2.24/9 *60=14.93 min

After turning to south ferry remains in radar for 6.7 min

So, it remains in radar zone for 14.93+6.7=21.63min

8 0

2 years ago