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-2x <2x-4
4 <4x
1 <x
2x-4 <4
2x <8
x <4
1 <x <4
Answer:
The gestation period of rhinos (487 days) is 121. 3 percent longer than the gestation period of bears (220 days).
Step-by-step explanation:
Given:
Gestation period of rhinos = 487 days
Gestation period of bears = 220 days
To Find:
Percentage increase = ?
Solution:
The percentage increase =
On substituting the values,
= 
=
=>
=> 121.3 %
Answer:
For this case we have the following info related to the time to prepare a return

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean
is given by:
And the standard deviation would be:

And the best answer would be
b. 2 minutes
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Solution to the problem
For this case we have the following info related to the time to prepare a return

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean
is given by:
And the standard deviation would be:

And the best answer would be
b. 2 minutes
Answer:
Quadrant IV
Step-by-step explanation:
Quadrant I = (+ , +)
Quadrant II = (- , +)
Quadrant III = (- , -)
Quadrant IV = (+ , -)
(1/2 , -1.8)
1/2 is +
1.8 is -
(+ , -)
It lies on Quadrant IV
For this case we have a function of the form:

Where,
A: initial amount
b: decrease rate
x: time in years
Substituting values we have:

For 2010 we have:
Answer:
an exponential decay function to model this situation is:
y = 1300 * (0.97) ^ x
The population in 2010 is:
y = 1083