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klemol [59]
2 years ago
7

My clock in the lounge room is 10 minutes slower than the clock on my phone which is 6 minutes slow. My tram always leaves 6 min

utes early although it is scheduled for 8:55 it takes me 20 minutes to get to the tram stop what time must I leave according to my lounge room clock in order to catch my tram
Mathematics
1 answer:
jasenka [17]2 years ago
7 0
So, the tram is scheduled to be about at 8:55, but it always leaves earlier by 6 minutes, so it really doesn't leave at 8:55 but 6 minutes before or 8:49, so you better be there at 8:49 to catch it.

the Phone Clock is slower by 6 minutes, so 8:49 on the phone will really be 8:43.

the Lounge Clock is slower than the Phone's by 10 minutes, so 8:43 on the phone is really 8:33 on the Lounge's Clock.

now to get to the tram stop, it takes you 20 minutes, so you can't go at 8:33 according to the lounge clock unless you're flash gordon, but you're not, it takes you 20 minutes to get there, so you need to leave 20 minutes before that, or 8:33 - 20 minutes, 8:13.
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Answer:

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Step-by-step explanation:

In the pictures attached, the options are shown.

The equation:

y+3=2(x+3)

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y-y₁=m(x-x₁)

where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:

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y = 3

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2 years ago
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lesantik [10]

Answer:

j=12

Step-by-step explanation:

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kvv77 [185]

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2 years ago
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Answer:

The correct option is D.

Step-by-step explanation:

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