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Darina [25.2K]
1 year ago
10

Is 4.567 a rational number

Mathematics
1 answer:
alisha [4.7K]1 year ago
4 0
<span>Yes, 4.567 is a rational number
</span>A rational number is a number that can be expressed as thequotient (i.e. ratio or fraction) of two integers. ( Integers arerational since any integer, n ,can be written as n/1 ) Rational numbers are numbers that can be expressed as fractionswhereas irrational numbers cannot be expressed as fractions A rational number is a number that terminates or ends. As in a perfect square like: 144; 36; 625 etc. More specifically, a rational number is a number that can be expressed as the ratio of two integers, where the denominator is not zero. 1.37, for instance, is rational because it can be expressed as 137 / 100. It is any whole number even if it's a negative number Any number that can be expressed as a fraction is a rational number whereas irrational numbers can't be expressed as a fractions. In mathematics, a rational number is any number thatcan be expressed as the quotient or fraction p/q of two integers, pand q, with the denominator q not equal to zero. Since q may beequal to 1, every integer is a rational number .
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Pulling out like terms

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2 years ago
"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt
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Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

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Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =30,\sigma =2)

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b. What is the standard error of the mean time?

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >31.25)=1-P(\bar X

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >28.25)=1-P(\bar X

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

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