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julsineya [31]
2 years ago
7

A health inspector must visit 44 of 1414 restaurants on monday. in how many ways can she pick a first comma second comma third c

omma and fourthfirst, second, third, and fourth restaurant to​ visit?
Mathematics
1 answer:
ira [324]2 years ago
4 0
Let's make clear the question, because it may be confusing:
<span>"A health inspector must visit 4 of 14 restaurants on Monday. In how many ways can she pick a first, second, third, and fourth restaurant to visit?"

In order to solve the problem, you need to use permutations: you have 14 possible restaurants to choose as first, the second one will be chosen among the 13 restaurants left, the third one among the remaining 12 and the fourth one will be one of the remaining 11.

Therefore, the total number of possibilities is:
14 </span>× 13 × 12 × 11 = 24024

There are <span>24024 possible ways to choose the four restaurants to visit.</span>
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For this case what you should do is create the equation based on:
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If r=[x,y,z] and r0=[x0,y0,z0], describe the set of all points (x,y,z) such that Ir-r0I =1.
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Answer:

The points (x,y,z) that respond to Ir-r0I =1, are all that describes the form (x-x_0)^2+(y-y_0)^2+(z-z_0)^2=1 with:

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Step-by-step explanation:

All points required in this problem came from applying the definition of modulus of a vector:

Ir-r0I =1.

|(x,y,z)-(x_{0},y_{0},z_{0})|=|(x-x_{0},y-y_{0},z-z_{0})|=\sqrt{(x-x_{0})^2+(y-y_{0})^2+(z-z_{0})^2}=1\\(x-x_{0})^2+(y-y_{0})^2+(z-z_{0})^2=1^2=1

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Answer:

Hey the answer is e i think

Step-by-step explanation:

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Answer:

My best answer is that the probability is 35/100 that the student chosen at random owns neither a laptop nor a mobile phone.

Step-by-step explanation:

If you go back and read the introductory passage, you will notice it says, "In a group of 100 students... 35 own either a laptop or a mobile phone, but not both." And I think the other numbers, I.E. 25 and 40, were just meant to throw us off. Therefore, I think 35/100 is the probability.

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