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2 years ago

Select the correct answer.

Mathematics

2 answers:

dem82 [27]2 years ago

8 0

Answer i got was c.

Step-by-step explanation:

Edmentum

damaskus [11]2 years ago

4 0

Answer:

None of the above.

Step-by-step explanation:

Let us check each of the answer choices one bye one.

Choice A: $y+41=(31*2)+77x$

solving for y we get:

$y=77x+21,$

which is not equal to our function h(x).

Choice B: $y=317+77x+41$ .

This gives $y=358+77x,$

which is not equal to our function h(x).

Choice C: $x+41=(31*2)+77x$ and $y=31x+77x-41$ .

The first expression does not contain y, thus it is not equivalent to h(x). The second equation already gives the value of y , and we see that it is not equal to h(x).

Therefore we conclude that none of the choices given are correct.

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Type two statements that use nextint() to print 2 random integers between (and including) 100 and 149. end with a newline. ex: 1

solong [7]

NB- Solution is emboldened

import java.util.Scanner;

import java.util.Random;

public class RandomGenerateNumbers {

public static void main (String [] args) {

Random randGen = new Random();

int seedVal = 0;

seedVal = 4;

randGen.setSeed(seedVal);

System.out.println(randGen.nextInt(50) + 100);

return;

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4 0

1 year ago

Read 2 more answers

Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t

Ber [7]

Answer:

The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

Step-by-step explanation:

The random variable X is defined as the amount of time until the next student will arrive in the library parking lot at the university.

The random variable X follows an Exponential distribution with mean, μ = 4 minutes.

The probability density function of X is:

$f_{X}(x)=\lambda e^{\lambda x};\ x\geq 0, \lambda >0$

The parameter of the exponential distribution is:

$\lambda=\frac{1}{\mu}=\frac{1}{4}=0.25$

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10}{0.25e^{-0.25x}}\, dx$

$=0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821$

Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

3 0

1 year ago

On a coordinate plane, square P Q R S is shown. Point P is at (4, 2), point Q is at (8, 5), point R is at (5, 9), and point S is

sergey [27]

Answer:

(D)The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.

Step-by-step explanation:

Point P is at (4, 2),
Point Q is at (8, 5),
Point R is at (5, 9), and
Point S is at (1, 6)

Midpoint of SQ $=\frac{1}{2}(1+8,5+6)=(4.5,5.5)$

Midpoint of PR $=\frac{1}{2}(4+5,2+9)=(4.5,5.5)$

Now, we have established that the midpoints (point of bisection) are at the same point.

Two lines are perpendicular if the slope of one is the negative reciprocal of the other.

In option D

Slope of RP =7

Slope of SQ $=-\dfrac17$

Therefore, lines RP and SQ are perpendicular.

Option D is the correct option.

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2 years ago

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Let

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