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wolverine [178]
2 years ago
10

Ariel left her home at 9 a.m., driving at 45 mph. At 11 a.m. her brother left the home and started after her at 60 mph. At what

time did Ariel's brother catch up with Ariel?
Mathematics
1 answer:
Vlada [557]2 years ago
6 0

Answer:

5:00 pm

Step-by-step explanation:

Let

x -----> the umber of hours

y ----> the total distance in miles

we know that

The distance is equal to the speed multiplied by the time

Find out the distance traveled by Ariel at 11:00 am

11:00 am-09:00 am=2 hours

45(2)=90 miles

so

<em>Ariel's linear equation is</em>

y=45x+90 ----> equation A

<em>Ariel's brother linear equation is</em>

y=60x ----> equation B

Equate equation A and equation B

60x=45x+90

Solve for x

60x-45x=90

15x=90

x=6\ hours

Adds 11:00 am + 6 hours=17:00 =5:00 pm

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Step 1

<u>Find the measure of angle x</u>

we know that

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we have that

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(8x+12)=78+78-------> 8x+12=156------> 8x=156-12

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Step 2

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so

3y-9=78------> 3y=87------> y=29°

therefore

<u>the answer is</u>

the measure of x is 18° and the measure of y is 29°


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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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