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postnew [5]
2 years ago
4

1. Use the given circle. Find the length s to the nearest tenth

Mathematics
2 answers:
dybincka [34]2 years ago
8 0
Part 1) <span>Find the length s to the nearest tenth

we know that
[length of a circumference]=2*pi*r
for r=3 in
</span>[length of a circumference]=2*pi*3------> 18.84 in

if 2*pi radians (full circle) has a length of------------> 18.84 in
 (5*pi/3) radians------------------------------> x
x=(5*pi/3)*18.84/(2*pi)--------> x=15.7 in

the answer Part 1) is 
15.7 in

Part 2) <span>What is the probability he will draw a blue tile on both draws?

we </span>have a bag of 5 red tiles, 3 yellow, 4 blue and 3 green
total tiles -----> 15

<span>4 blue out of 15
</span><span>1st draw is 4/15 
</span><span>2nd draw is 4/15
(4/15)*(4/15)-----> 16/225

the answer Part 2) is
16/225 </span>
Nady [450]2 years ago
8 0

Answer:

number 2. c. 16/225

Step-by-step explanation:

i took the exam

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How many weeks of flea treatment would Jim’s dog get from one package if each treatment only lasted 3 weeks In a normal year whe
4vir4ik [10]

Solution

Number of weeks in a year = 52 weeks

If in a normal year when each package of flea treatment lasts for 4 weeks, then in a year there Jim's dog will have to be treated for

\frac{52}{4} =13 times

Where as, when the fleas are bad in a year, the treatment lasts for only 3 weeks.

Then in a year Jim's dog would get

\frac{52}{3} =17 times


So Jim's dog will get 17- 13 =4 treatments more.

4 treatments that are made in 3 weeks each will be 4×3 =12 weeks more treatment

4 0
2 years ago
The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t^2 - 0.5t + 3.
Bingel [31]
The average rate of change (m) is the ratio of the change in function value to the width of the interval:
  m = (f(6) - f(2))/(6 - 2)

To compute this, we need to compute f(6) and f(2).
  f(6) = (0.25*6 -0.5)*6 +3.5 = 9.5
  f(2) = (0.25*2 - 0.5)*2 +3.5 = 3.5
Then the average rate of change is
  m = (9.5 - 3.5)/(6 - 2) = 6/4 = 1.5

The average rate of change is 1.5 thousand owners per year.
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2 years ago
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Find the geometric mean of 16 and 25. Round your answer to the nearest tenth
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Answer:

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Step-by-step explanation:

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Adult panda weights are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds. The largest pandas
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Answer:

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Step-by-step explanation:

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