Adult panda weights are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds. The largest pandas
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Answer:
Step-by-step explanation:
Hello!
X₁: speed of a motorcycle at a certain intersection.
n₁= 135
X[bar]₁= 33.99 km/h
S₁= 4.02 km/h
X₂: speed of a car at a certain intersection.
n₂= 42 cars
X[bar]₂= 26.56 km/h
S₂= 2.45 km/h
Assuming
X₁~N(μ₁; σ₁²)
X₂~N(μ₂; σ₂²)
and σ₁² = σ₂²
<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>
The parameter of interest is μ₁-μ₂
(X[bar]₁-X[bar]₂)± *
[(33.99-26.56) ± 1.654 *()]
[6.345; 8.514]= [6.35; 8.51]km/h
<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>
[(475.12-321.34) ± 2.485 *()]
[121.96; 185.60]
I hope this helps!
I found a similar problem to your problem here, which is shown in the attached picture. So, from the picture, we have to find the equation for the red line. All we have to do is find two points of the line. That would be: Point 1(2,0) and Point 2(-2,3). The general equation would be:
y - y₁ = (y₂-y₁)/(x₂ - x₁) * (x - x₁)
Substituting the coordinates to the equation,
y - 0 = (3-0)/(-2 - 2) * (x - 2)
y = -3(x -2)/4
Rearranging,
<em>4y = -3x + 6 or 4y + 3x = 6</em>
y - y₁ = (y₂-y₁)/(x₂ - x₁) * (x - x₁)
Substituting the coordinates to the equation,
y - 0 = (3-0)/(-2 - 2) * (x - 2)
y = -3(x -2)/4
Rearranging,
<em>4y = -3x + 6 or 4y + 3x = 6</em>