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Ivan
2 years ago
15

A high school band director has 120 students in his marching band. The marching band plays at all football games, so the band mu

st travel by school bus to each away game. The band director knows that each school bus holds 60 students. Which of the following best describes a method of assigning the band students to the two school buses so that each band student has a fair chance of being selected for either school bus? There is no way to assure that each band student has a fair chance of being selected for either bus. Randomly assign each student an unique number ranging from 1 to 120. Label colored balls with each number that is assigned to a student. Place all of the labeled balls into a bin, and randomly select 60 balls. The students with numbers found on the first 60 randomly selected balls will be assigned to the first school bus, and the remaining 60 students will be assigned to the second school bus. Using a random number generator, assign each band student a number, eliminating duplicate numbers. Assign each band student with a positive number to the first school bus, and assign each band student with a negative number to the second school bus. Using a random number generator, assign each band student a number, eliminating duplicate numbers. Assign each band student with an even number to the first school bus, and assign each band student with an odd number to the second school bus.
Mathematics
2 answers:
lidiya [134]2 years ago
4 0

Randomly assign each student an unique number ranging from 1 to 120. Label colored balls with each number that is assigned to a student. Place all of the labeled balls into a bin, and randomly select 60 balls. The students with numbers found on the first 60 randomly selected balls will be assigned to the first school bus, and the remaining 60 students will be assigned to the second school bus.

umka2103 [35]2 years ago
3 0
The first method is the best because 60+60=120 so either way even if you were picked randomly you will get a seat on the bus.
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Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each
sp2606 [1]
Lets take Gregs weight as “x”. This means that Justins weight is x-15, and x/2 = (x-15)-75.

If we take that last equation, lets combine like terms:

x/2 = x - 15 - 75
x/2 = x - 90
Now multiply both sides by 2 to get rid of the fraction
x = 2x - 180
Subtract 2x from both sides
x - 2x = -180
-x = -180
x = 180 — this is Gregs weight

Justins weight is x-15, so 180-15, which is 165 pounds. Hope this helped.
5 0
2 years ago
michael wittry has been investing inhis roth IRA retirement account for 20 years. Two years ago his account was worth $215,658.
Over [174]
Let's say

a = 215,658

ok... so.. he first lost 1/3 of that

\bf \textit{\underline{lost} }\frac{1}{3}a\qquad  \qquad  a-\cfrac{1}{3}a\implies a-\cfrac{a}{3}\implies \cfrac{3a-a}{3}\implies \cfrac{2a}{3}
\\\\\\
\textit{then he \underline{gained} }\frac{1}{2}\textit{ of }\frac{2a}{3}\qquad \qquad \cfrac{2a}{3}+\cfrac{\frac{2a}{3}}{2}\implies \cfrac{\frac{2a}{3}}{\frac{2}{1}}
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\cfrac{2a}{3}+\cfrac{2a}{3}\cdot \cfrac{1}{2}\implies \cfrac{2a}{3}+\cfrac{2a}{6}\implies \cfrac{4a+2a}{6}
\\\\\\
\cfrac{6a}{6}\implies \boxed{a}\implies 215,658


so, his nickname might just be even steven, because, he ended up with the same original amount after the 1/2 bump.
4 0
2 years ago
Estimate the value of 9.9 squared x 1.79
Helen [10]
9.9^2X1.79
9.9^2=98.01
98.01X1.79=175.4379
7 0
2 years ago
Read 2 more answers
Which graph shows the solution to the system of linear inequalities?
ICE Princess25 [194]

Answer:

x = 6 ; Rewritten: 2x-3y-12=0 ; y=-4

Step-by-step explanation:

2x-3 multiply 0=12

x=6 ( that's the function)

Rewritten steps: 2x-3y=12 then move constant to the left by adding its opposite to both sides which gives you 2x-3y-12=12-12. After the sum of two opposites equals 0 which is 2x-3y-12=0

Y Intercept :

2x-3y=12 and to find y intercept, sub x = 0 ; to 2 multiply 0 -3y=12 and then you solve for the equation which is your answer.

7 0
2 years ago
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this squared based pyramid is cut horizontally at a height of 15cm to leave this frustum base area=10cm
scoundrel [369]

Answer:

583.33 cm³

Step-by-step explanation:

From the image attached, the total height (H) of the pyramid is 30 cm, the height of the frustrum (h) = 15 cm, the Frustrum base = lower base = B = 10 cm . To find the length of the upper base (b), we use:

\frac{b}{H-h}=\frac{B}{H}\\  b=(H-h)\frac{B}{H}\\b=(30-15)\frac{10}{30}=5\\b=5\ cm

The volume of the frustrum is given by:

V=\frac{1}{3}h(B_1+B_2+\sqrt{B_1B_2} )\\ Where\ B_1\ is \ the\ area \ of\ the\ upper\ base= 5cm*5cm=25cm^2\\B_1\ is \ the\ area \ of\ the\ lower\ base= 10cm*10cm=100cm^2\\V=\frac{1}{3}(10)(25+100+\sqrt{25*100} )=583.33\\V=583.33\ cm^3

6 0
2 years ago
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