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bonufazy [111]
2 years ago
8

Devon purchased a new car valued at $16,000 that depreciated continuously at a rate of 35%. Its current value is $2,000. The equ

ation mc025-1.jpg represents the situation, where t is the age of the car in years and r is the rate of depreciation. About how old is Devon’s car? Use a calculator and round your answer to the nearest whole number.
Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
7 0

Cost =16000
rate of depreciation = 35%
written down value = 2000
depreciation for one year =16000*35% = 5600
5600*2 = 11200+5600*6\12 = 2000
the car is 2.5 years old. It has been depreciated for 2 whole years and half years.

Andrej [43]2 years ago
7 0

Answer:

5 years

Step-by-step explanation:

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First month she payed 1451 dollars

Second month she payed 1/3 of that, which is:
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2 years ago
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The average blood alcohol concentration (bac) of eight male subjects was measured after consumption of 15 ml of ethanol (corresp
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Answer:

After 5 minutes, the BAC was increasing at the rate of 0.0137 mg/mL a minute.

Step-by-step explanation:

The average blood alcohol concentration (bac)  is modeled by the following function.

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In which t is measured in minuted.

How rapidly was the BAC increasing after 5 minutes?

This is c'(t) when t = 5.

Using the derivative of the product.

Derivative of the product:

c(t) = f(t)*g(t)

c'(t) = f'(t)*g(t) + f(t)*g'(t)

In which problem:

f(t) = 0.0225t

g(t) = e^{-0.0467t}

So

c'(t) = 0.0225e^{-0.0467t} - 0.0225*0.0467*te^{-0.0467t}

c'(5) = 0.0225e^{-0.0467*5} - 0.0225*0.0467*5e^{-0.0467*5} = 0.0137

After 5 minutes, the BAC was increasing at the rate of 0.0137 mg/mL a minute.

3 0
2 years ago
The gas mileage for a certain vehicle can be approximated by m=−0.05x2+3.5x−49, where x is the speed of the vehicle in mph. Dete
Whitepunk [10]

Answer:

<h2>14mph</h2>

Step-by-step explanation:

Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;

m = −0.05x²+3.5x−49

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9 = −0.05x²+3.5x−49

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x = -70+97.7/2

x = 27.7/2

x = 13.85mph

x ≈ 14 mph

Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph

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Answer:

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Step-by-step explanation:

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