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RUDIKE [14]
2 years ago
15

it looks as though you made 72 of your goal so far for the month you only have 5 days left to reach 100% of your goal let me rem

ind you that your target was 45 renewals how many renewals in the next 5 days
Mathematics
2 answers:
dezoksy [38]2 years ago
8 0
72% can also be written as 0.72, so take 0.72 x 45 = 32.4     

Subtract 32.4 from 45    45 - 32.4 = 12.6    You need 12.6 renewals in 5 days.
Sonja [21]2 years ago
6 0
72% can also be written as 0.72, so take 0.72 x 45 = 32.4     

Subtract 32.4 from 45    45 - 32.4 = 12.6 

You need 12.6 renewals in 5 days
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1) Consider the sequence:
Ivan

Answer:

1) The 38th term is A. 38

2) The 11th term is D. 3072

3) The 3rd term is C. 34

Step-by-step explanation:

1) I added 2 until I got to the 38th term.

2) I multiplied until I got to the 11th term.

3) I added 3 until i got to the 12th term.

The teacher showed a more complex way to do it but this is just what I did.

I took the quiz, so I know that I got them all correct.

5 0
2 years ago
Read 2 more answers
Jake's morning run was a distance of 9.3 miles. He ran back and forth on one long straight street. He started at his house and r
Sergeeva-Olga [200]

Answer: the distances can be 0.65 miles (in the opposite direction to the school) or 4.65 miles (in the same direction as the school)

Step-by-step explanation:

Ok, the data that we have is:

Total distance = 9.3 mi.

The travel is:

House to school = 4 mi.

school to library = A

library to house = B

Now, we have that:

4mi + A + B = 9.3mi.

We have three possibilities:

1) The order of locations is: house, library, school

The travel from: school to library + library to house is equivalent to a travel between the school to the house = 4mi.

Then we have A + B = 4mi

4mi + A + B = 8mi ≠ 9.3mi

Then the library can not be between the house and the school.

2) The order of locations is: house, school, library.

In this case we have that the distance between the library and the house is equal to the distance between the house and the school plus the distance between the school and the library, then:

4mi + A = B.

We can replace this in our original equation:

4mi + A + B = 9.3mi

4mi  + A + (4mi + A) = 9.3mi

8mi + 2*A = 9.3mi

2*A = 9.3mi - 8mi = 1.3mi

A = 1.3mi/2 = 0.65mi

Then the distance between the house and the library is:

The 4 miles between the house and the school, plus the 0.65 miles between the school and the library:

Distance = 4mi + 0.65mi. = 4,65mi

3) The third case is when the order of the locations is:

Library, house, school.

Then the distance between the house and the library is equal to the distance between the school and the library minus the distance between the house and the school, this is:

A - 4mi = B

Now we can replace this in our distance equation:

4mi + A + B = 9.3mi

4mi + A + (A - 4mi) = 9.3 mi

2A = 9.3mi

A = 9.3mi/2 = 4.65mi

Then the distance between the house and the library is:

B = A - 4mi = 4.65mi - A = 0.65mi

Then the distance between the house and the library is 0.65 miles in this case.

7 0
2 years ago
Mike has a net spendable income of $1,400. He decides to set up a budget before looking for an apartment or a car. He sets up hi
barxatty [35]
This might be a problem considering he would have no money left considering unless I made a mistake all the numbers add up to 1,400 so considering this he won't have money to spend if he get in a situation that he needs to spend

(I am not 100% sure this is the answer you are looking for)
5 0
2 years ago
Read 2 more answers
Solve the equation -10 (g - 6) = -65
Elanso [62]

Step-by-step explanation:

- 10(g - 6) =  - 65 \\  - 10g + 60  =  - 65 \\  - 10g =  - 125 \\   10g = 125 \\ g =  \frac{25}{2}

5 0
2 years ago
The following table shows the annual income, in dollars, and amount spent on vacation, in dollars, for a sample of 8 families.
marishachu [46]

Answer:

a. Scatterplot is attached.

b. Positive Correlation

c. Correlation coefficient=0.9219

Step-by-step explanation:

a.

The following procedure will be used to obtain the scatter plot

  •    Open an Google Sheets file online or excel sheet on your computer.
  •    In column B and C, enter  the Income and Vacation data  as provided above.
  •    Select the data > click on insert CHART.
  •    Chose Scatter Chart option
  •    Click OK.

A scatter plot visualizing your data should be displayed as attached.

b.

  • On your computer, open a spreadsheet in Google Sheets.
  • Double-click on your scatter plot.
  • At the right, click on Customize  tab and then Series.
  • Scroll down and check the Trend line box

-From the trend line, your notice that your variables have a positive correlation.

-As the income increases, so does vacation expenditure.

c. The correlation coefficient can be calculated as follows.

  • Click on any empty cell in the sheet and enter the formula
  • "=CORREL((y-axis range),(x-axis range))"
  • ENTER

-From our Google Sheets calculation our variables have a positive correlation and the correlation coefficient is 0.9219

-The correlation coefficient,r can also be calculated manually:

-let x be income, and y be vacation and divide all the values by 100 to make the smaller and easier to manipulate:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2-(\sum x)^2][n\sum y^2-(\sum y)^2}}\\\\\\\sum xy=153914\\\sum x=4485\\\sum y=246\\\sum x^2=2878447\\(\sum x)^2=4485^2=20115225\\(\sum y)^2=246^2=60516\\\sum y^2=8392\\n=8\\\\\#substitute \ and \ solve \ for \ r\\\\=\frac{8\times153914-4485\times 246}{\sqrt{[8\times 2878447-4485^2][8\times 8392-246^2]}}\\\\=0.92186\\\\\approx 0.9219

4 0
2 years ago
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