Given :
Rate = 75 m 1 s×60 s 1 min×1 h 60 m.
To Find :
Correct answer after conversion.
Solution :
We know, 1 min = 60 sec.
1 hour = 60 min = 60×60 sec = 3600 sec.
Putting value of min and hour in seconds , we get :
Hence, this is the required solution.
Answer:
A) 10.75 is the concentration of arsenic in the sample in parts per billion .
B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.
C) It will take 1.37 years to remove all of the arsenic from the lake.
Explanation:
A) Mass of arsenic in lake water sample = 164.5 ng
The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.
To calculate the ppm of oxygen in sea water, we use the equation:
Both the masses are in grams.
We are given:
Mass of arsenic = 164.5 ng =
Volume of the sample = V =
Density of the lake water sample ,d=
Mass of sample = M =
10.75 is the concentration of arsenic in the sample in parts per billion.
B)
Mass of arsenic in of lake water =
Mass of arsenic in lake water be m.
Mass of arsenic in lake water :
1 g = 0.001 kg
7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg
7,633.66 kg the total mass of arsenic in the lake that the company have to remove.
C)
Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.
Days required to remove 1 kilogram of arsenic from the lake water :
Then days required to remove 7,633.66 kg of arsenic from the lake water :
1 year = 365 days
499.19 days =
It will take 1.37 years to remove all of the arsenic from the lake.
Answer:
2.83 g
Explanation:
At constant temperature and pressure, Using Avogadro's law
Given ,
V₁ = 2.12 L
V₂ = 3.12 L
n₁ = 0.120 moles
n₂ = ?
Using above equation as:
n₂ = 0.17660 moles
Molar mass of methane gas = 16.05 g/mol
So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g
<u>2.83 g are in the piston.</u>