Compound j is optically active and has the molecular formula c6h10 and has a four carbon ring. on catalytic hydrogenation, j is
converted to k (c6h12) and k is optically inactive. propose structures for j and k. (draw a three-dimensional formula for each using dashes and wedges around chiral centers.) j (draw one of the enantiomers):
1 answer:
The two possible enantiomers for the starting material and the products are shown below,
Where;
J = (S)-1,4-dimethylcyclobut-1-ene
Or,
J = (R)-1,4-dimethylcyclobut-1-ene
And,
K = 1,2-dimethylcyclobutane
Both enantiomers have same molecular formula (C₆H₁₀) but different stereochemistry about chiral carbon.
Upon catalytic hydrogenation two hydrogen atoms are added across double bond resulting in the formation of cyclobutane.
Where;
J = (S)-1,4-dimethylcyclobut-1-ene
Or,
J = (R)-1,4-dimethylcyclobut-1-ene
And,
K = 1,2-dimethylcyclobutane
Both enantiomers have same molecular formula (C₆H₁₀) but different stereochemistry about chiral carbon.
Upon catalytic hydrogenation two hydrogen atoms are added across double bond resulting in the formation of cyclobutane.
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