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Juli2301 [7.4K]
2 years ago
10

Consider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2] [I–] [H+] rate I 0.100 M 5.00 × 10–4 M

1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec Two mechanisms are proposed: I. II. Which mechanism and which step as the rate determining step would best fit the data?

Chemistry
1 answer:
otez555 [7]2 years ago
4 0

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem

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Given six molecules, identify the molecules with polar bonds and the molecules that are polar.CCl4, CH3Cl, H20, CO2, O2
Nikitich [7]

Answer:

Non-polar compounds: CCl_4, O_2, CO_2

Polar compounds: CH_3Cl, H_2O

Explanation:

For this question, we must start with the <u>Lewis structure</u> for each molecule and then we can do their respective analysis:

-) CCl_4

In this case, we have 4 equal atoms attached to the central atom. Therefore, we have the <u>same magnitude</u> of electronegativity. Chlorine atoms have <u>different and opposite directions.</u> Therefore due to the orientation the dipole moments cancel and the <u>net dipole moment will be zero</u> and the molecule will be non-polar.

-) O_2

In this case, we have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the <u>opposite</u>. Therefore the dipole moments are canceled and the molecule will be <u>non-polar</u>.

-) CO_2

In this case, we also have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the <u>opposite</u>. Therefore the dipole moments are canceled and the molecule will be <u>non-polar</u>.

-) CH_3Cl

For this molecule, we have a <u>different atom</u>. The hydrogen atom, therefore the magnitude of one of the atoms attached to the central atom is different and the magnitude of the <u>net dipole moment will be different from zero</u> and the molecule will be <u>polar</u>.

-) H_2O

For this molecule, due to the structure of the molecule, the dipole moments of oxygens <u>will not have a totally opposite configuration</u>. Therefore, the net dipole moment will be different from zero and the molecule will be <u>polar</u>.

See figure 1 to further explanations

I hope it helps!

5 0
2 years ago
in collecting the precipitate, why would it be inappropriate to heat the reacted mixture and evaporate off the water?
djverab [1.8K]
In collecting the precipitate, it is inappropriate to heat <span>the reacted mixture and evaporate off the water because it is possible that the mixture contains other substances that precipitates as well when the mixture is being heated so you will not be able to collect what you want.</span>
6 0
2 years ago
Danny sails a boat downstream. The wind pushes the boat along at 21 km/hr. The current runs downstream at 15 km/hr. What is the
deff fn [24]

Answer: D) 36.0 km/hr, downstream

Explanation:

For downstream motion of the boat, the actual velocity of the boat is the sum of velocity of the water current and the velocity of the boat due to pushed by wind.

Velocity of water current, v = 15 km/h

Velocity of the boat going downstream, u = 21 km/h

Actual velocity of the boat = v'

v' = v + u

⇒v' = 15 km/h + 21 km/h

⇒u = 21 km/h +15 km/h = 36.0 km/h downstream

Thus, the correct answer is option D.

7 0
2 years ago
Read 2 more answers
Adding one proton to the nucleus of an atom
Sonbull [250]
Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.
7 0
2 years ago
4.8g of calcium is added to 3.6g of water. The following reaction occurs
notka56 [123]
Q1)
the number of moles can be calculated as follows
number of moles = mass present / molar mass
number of moles is the amount of substance.
4.8 g of Ca was added therefore mass present of Ca is 4.8 g
molar mass of Ca is 40 g/mol 
molar mass is the mass of 1 mol of Ca
therefore if we substitute these values in the equation 
number of moles of Ca = 4.8 g / 40 g/mol = 0.12 mol
0.12 mol of Ca is present 

q2)
next we are asked to calculate the number of moles of water present 
again we can use the same equation to find the number of moles of water
number of moles = mass present / molar mass
3.6 g of water is present 

sum of the products of the molar masses of the individual elements by the number of atoms 
H - 1 g/mol and O - 16 g/mol 
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molar mass of H₂O is 18 g/mol 
therefore number of moles of water  = 3.6 g / 18 g/mol = 0.2 mol 
0.2 mol of water is present 
8 0
2 years ago
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