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jonny [76]
2 years ago
12

PLEASE HELP ME!!!!!! The transportation department of Fredrick Inc. wanted to know the mode of transport used by their employees

to commute to work. The survey was conducted by randomly asking 150 employees on a day when the factory had an attendance of 1,526 employees. The survey reported that 56% of those surveyed used public transportation to commute to work. Assuming a 95% confidence level, which of the following statements holds true?
A.As the sample size is appropriately large, the margin of error is ±0.079.

B.As the sample size is too small, the margin of error is ±0.079.

C.As the sample size is appropriately large, the margin of error is ±0.094.

D.As the sample size is too small, the margin of error cannot be trusted.
Mathematics
1 answer:
aivan3 [116]2 years ago
3 0

The sample size is 150. If the sample size is greater than 30 we consider it an appropriate large sample size and can consider the population to be normally distributed. Since sample size is quite larger than 150, we assume that the sample is from the population which is normally distributed.

We are given the sample proportion p = 0.56

Sample Size = n = 150

We have to construct 95% confidence interval about the sample proportion. The z value corresponding to 95% confidence interval is 1.96. The formula to calculate the margin of error (E) is:

E= ± z\sqrt{\frac{p(1-p)}{n}}

Using the values in the above formula, we get:

E =± 1.96\sqrt{\frac{0.56(1-0.56)}{150}}

E = ± 0.079

Therefore, the correct option is:

A. As the sample size is appropriately large, the margin of error is ±0.079.

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You offer senior citizens a 20 percent discount on their meal prices served at your cafeteria. Assuming that an average of 150 s
scoray [572]

Given, there are an average of 150 citizens eat daile in the cafeteria.

The average price of their meals = $5.95.

The discount given for sinior citizens in their meals = 20%

So we have to find 20% of $5.95 first.

20% of $5.95 = (5.95)(\frac{20}{100} )

= \frac{(5.95)(20)}{100}

= \frac{119}{100}

= 1.19

So, the amount of discount given to the senior citizens = $1.19 per head.

As there are 150 cinior citizens daily.

So total discount given daily = $(150)(1.19) =$178.5

So we have got the required answer.

Option C is correct here.

3 0
2 years ago
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Which values of m and b will create a system of equations with no solution? Select two options. y = mx + b y = –2x + A system of
Nuetrik [128]

Answer:

m = -2 and b = -1/3

m = -2 and b = -2/3.

Step-by-step explanation:

y = -2x - 1/3

y = -2x - 2/3

This system has no solutions because y cannot be 2 different values at once.

5 0
1 year ago
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A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un
Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

H_{0}:p1=p2

H_{a}:p1≠p2

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }  where

  • p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
  • p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
  • p is the pool proportion of p1 and p2 (\frac{15+12}{100+100}=0.135)
  • n1 is the sample size of the students from West University (100)
  • n2 is the sample size ofthe students from East University (100)

Then we have z=\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } } ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0
1 year ago
A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x
Fudgin [204]

Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

<u><em>That would be number of units sold to get max revenue.</em></u>

<u><em /></u>

<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>

<u />

Before differentiating, we see the rules shown below:

f(x)=ax^n\\f'(x)=n*ax^{n-1}

Where

f'(x) is the differentiated function

Now, let's do the process:

r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000

So, 1000 units need to be sold for max revenue

Now, substituting, we get:

r (x)=700x-0.35x^2\\r(1000)=700(1000)-0.35(1000)^2\\r(1000)=350,000

The max revenue amount is $350,000

5 0
2 years ago
Find the equation of the line below if necessary use the slash (/) to indicate a division bar (2,6)(1,3)
777dan777 [17]
Given that the line passes through points:
(2,6), (1,3)
the equation will be given by:
m(x-x1)=y-y1
where
slope, m=(y-y1)/(x-x1)
from the points given:
m=(6-3)/(2-1)=3/1=3
thus the equation will be given by:
using point (1,3)
3(x-1)=y-3
3x-3=y-3
hence
y=3x-3+3
y=3x
Answer: y=3x
7 0
2 years ago
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