All categories

2 years ago

Techechtium-99m has a half-life of 6 hours. If 1000mg is in use, in how many hours will 62.5mg remain?

1 answer:

7 0

One half life 1000 mg to 1000/2 =500 mg
One half life 500 mg to 500/2 = 250 mg
One half life 250 mg to 250/2 = 125 mg
Etc .......

You might be interested in

The volume of an object that is 23 ft wide, 10 ft deep, and 8 ft height is:

monitta

The answer is 1840 because you have to do 10x8 then multiply that by 23 and get 1840

6 0

2 years ago

Read 2 more answers

Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.

Darina [25.2K]

Answer:

There is no solution for the given radical equation.

x = 225/16 is an extraneous solution.

Step-by-step explanation:

The given equation is

Add 3 to both sides of the equation

Squaring both sides

Divide both sides by 16

Substituting back the value of x in original equation to check the extraneous solution.

Since -18≠ 12. Hence, the value of x does not satisfy the equation.

Therefore, x = 225/16 is an extraneous solution.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A sports company wants to package a ball with a 1.5-inch radius in sets of two. They have two options: a cylinder or a square pr

guajiro [1.7K]

Step 1

Find the Volume of the two balls

we know that

the Volume of a sphere is equal to

$V=\frac{4}{3} \pi r^{3}$

In this problem we have

$r=1.5\ in$

Substitute

$V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}$

the volume of the two balls is equal

$V=2*4.5\pi=9 \pi\ in^{3}$

Step 2

Find the volume of a cylinder

we know that

The Volume of a cylinder is equal to

$V=\pi r^{2}h$

In this problem we have

$r=1.5\ in$

$h=4*r=4*1.5=6\ in$

Substitute

$V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}$

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

$13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}$

Step 4

Find the volume of the square prism

The volume of the prism is equal to

$V=Bh$

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

$B=(2*1.5)^{2}=9\ in^{2}$ -----> the base is equal to the diameter

$h=4*r=4*1.5=6\ in$

Substitute

$V=9*6=54\ in^{3}$

Step 5

Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

$54\ in^{3}-9\pi\ in^{3}=25.73\ in^{3}$

Step 6

Compare the amount of wasted space

the amount of wasted space in the cylinder is $14.14\ in^{3}$

the amount of wasted space in the prism is $25.73\ in^{3}$

Find the difference

$25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}$

The package that has the least amount of wasted space is the cylinder

therefore

<u>the answer is the option</u>

the cylinder because it has approximately 11.6 in.3 less wasted space than the prism

5 0

2 years ago

Read 2 more answers

One printing machine printed 500 books in 40 hours this week. A second printing machine printed for 30 hours this week but print

babunello [35]

The second machine would print 750 books in 30 hours that week.

3 0

2 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

kobusy [5.1K]

Answer:

g(n) = 0.05·2^n

Step-by-step explanation:

The paper with no folds is 0.05 mm thick. Each fold multiplies the thickness by 2, so the function is ...

g(n) = 0.05·2^n

_____

<em>Comment on paper folding</em>

In practice, where the paper must bend around the fold, it is impossible to fold an ordinary piece of paper 9 times. You may be able to fold a very large, very thin piece of paper that many times.

8 0

2 years ago