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2 years ago

What is the m∠ACB? 10° 50° 90° 180°

Mathematics

2 answers:

qwelly [4]2 years ago

9 0

The total sum of angles in a triangle is 180, thus the value of ∠ACB will be obtained as follows:
Given that the triangle is a right triangle, the sum of angles will be:
(4x)°+(7x-20)°+90=180
simplifying and solving for x we get:
4x+7x-20+90=180
11x=180+20-90
11x=110
dividing both sides by 11 we get:
(11x)/11=110/11
this gives us
x=10°
Thus substituting the value of x in:
∠ACB=(7x-20)°
=(7*10-20)
=70-20
=50°

Answer: 50°

mixer [17]2 years ago

7 0

Answer : The Answer Is 50

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We have that

Cost use of a backhoe----------------------$300 an hour

Estimate for equipment rental each week---------------------$18,400

Total hours operator per week--------------------------------------40

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2 years ago

Which of the following estimates at a 95% confidence level most likely comes from a small sample?

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The correct answer is:

A) 60% ± 18%.

Explanation:

In a confidence interval, the margin of error is given by z*(σ/√n), where σ is the standard deviation and n is the sample size.

First we find the value of z:

We want a 95% confidence level; 95% = 95/100 = 0.95.

To find the z-score, we first subtract this from 1:
1-0.95 = 0.05.

Divide by 2:
0.05/2 = 0.025.

Subtract from 1 again:
1-0.025 = 0.975.

Using a z-table, we find this value in the middle of the table. The z-score that is associated with this value is 1.96.

Back to our formula for margin of error, we have 1.96(σ/√n). The larger n, the sample size, is, the larger its square root is. When we divide by a larger number, our answer is smaller; this gives us a smaller margin of error.

This means that if we had a small sample size, we would divide by a smaller number, making our margin of error larger. The largest margin of error we have in this question is 18%, so this is our correct answer.

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2 years ago

Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.

Ede4ka [16]

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

Step-by-step explanation:

We need to describes Catron’s error?

The steps are:

Step 1: (Negative 9) (2 + two-fifths)

Step 2: (Negative 9) (Negative 2) + (negative 9) (two-fifths)

Step 3: Negative 18 + (negative 9) (two-fifths)

Step 4: (negative 27) (two-fifths)

Solution: Negative StartFraction 54 over 5 EndFraction = Negative 10 and four-fifths

The error is:

She incorrectly broke up 2 and two-fifths.

Option A is correct option.

Solving

Solving the equation by removing the error:

Step 1: (Negative 9) (2 + two-fifths)

taking LCM of 2 and two-fifths (2/5)

Step 2: (Negative 9) (twelve-fifths)

Step 3: (Negative 9*twelve)-fifths

Step 4: Negative one hundred and eight- fifths

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Keywords: Solving Expressions

Learn more about Solving Expressions at:

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2 years ago

Read 2 more answers

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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2 years ago

3. Adrian kept an eye on the basketball game score by looking online every 10 minutes. Over the course of

Montano1993 [528]

Answer:

3. Adrian kept an eye on the basketball game score by looking online every 10 minutes. Over the course of

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by 4 points. All other times, the two teams were tied.

(a) What is the average score of Adrian’s favorite team relative to its opponent using the observations

Adrian made during the game? Show your work neatly.

(b) Explain what this value means about Adrian’s favorite team’s performance

Step-by-step explanation:

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1 year ago