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Anika [276]
2 years ago
7

What is the smallest possible value for the product of 2 integers that differ by 7

Mathematics
1 answer:
Nookie1986 [14]2 years ago
3 0
Let 2 integers that differ by 7 <span>are x , x+7
</span>
let the product of the <span>2 integers that differ by 7 is y
</span><span>
</span>
<span>∴ y = x(x+7) = x² + 7x
</span><span>
</span>
<span>By graphing y = x² + 7x ⇒⇒⇒ see the attached figure
</span>
There is a minimum point at x = -3.5  which give y = -12.25
∵ The product of two integers will be an integer number
So, the nearest integer number to the minimum value = -12

∴ <span>The smallest possible value for the product of 2 integers that differ by 7 is (-12)
</span>


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Answer:

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Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

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Hence, we have:

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Step-by-step explanation:

Given central angle PQR = 45°

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