Question

Triangle EFG has vertices E(–3, 4), F(–5,–1), and G(1, 1). The triangle is translated so that the coordinates of the image are E'(–1, 0), F'(–3, –5), and G'(3, –3).
Which rule was used to translate the image?

A. T 4,–4(x,y)
B. T –4,–4(x,y)
C. T 2,–4(x,y)
D. T –2, –4(x,y)


Thanks y’all:)

Answer 1

Answer with explanation:

Vertices of ΔEFG =E(–3, 4), F(–5,–1), and G(1, 1)-----Pre Image

Vertices of ΔE'F'G' =E'(–1, 0), F'(–3, –5), and G'(3, –3). ----Image

$E_{(-3,4)}=(-3+2, 4-4)=E'_{(-1,0)}\\\\F_{(-5,-1)}=(-5+2,-1-4)=F'_{(-3,-5)}\\\\G_{(1,1)}=(1+2,1-4)=G'_{(3,-3)}$

Option C

  Translation of Vertices of triangle that is Pre image has taken place , 2 units Horizontally right and 4 unit vertically down to obtain vertices of Image.

  $T_{(2,-4)}(x,y)$

Answer 2

Most likey c becasue ik cause im smart and i know how to do this ur welome i think