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Minchanka [31]
2 years ago
4

Tsunamis are dangerous! Scientists use the formula s=\sqrt(9.8d) to calculate the speed (s) of the tsunami (in meters per second

) based on the depth (d) of the ocean (in meters). The 9.8 refers to the acceleration of the tsunami due to gravity, in meters per second squared. What is the depth of the ocean (to the nearest meter) if the tsunami is moving at a speed of 320 meters per second?
Mathematics
1 answer:
shtirl [24]2 years ago
5 0
Given that the speed of a tsunami is measured by the formula s= \sqrt{9.8d}.

Given that a <span>tsunami is moving at a speed of 320 meters per second, then we have:

</span>320= \sqrt{9.8d}  \\  \\ \Rightarrow9.8d=320^2=102,400 \\  \\ \Rightarrow d= \frac{102,400}{9.8} =10,448.98\ meters
<span>
Therefore, the depth of the ocean is 10,448.98 meters.</span>
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A group of friends wants to go to the amusement park. They have $469.75 to spend on parking and admission. Parking is $10.75, an
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Answer:

12

Step-by-step explanation:

469.75-10.75 =

459 ÷ 38.25 =

12

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Jose receives a $10 gift card for downloading music and wants to determine how many songs he can purchase. Each downloaded song
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With the $10 gift card, Jose can buy at most 8 songs

x(the number of songs) less than or equal to 8

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Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average
lutik1710 [3]
Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5

Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.
4 0
2 years ago
Read 2 more answers
Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a differen
Anna007 [38]

Answer:

5 miles.

Step-by-step explanation:

Consider the question: Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a different route taking 2 1/2 hours. How many miles did Jinghua hike on the return trip ?

First of all, we will find Jinghua's speed using given information as:

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Convert mixed fractions into improper fractions:

4\frac{1}{2}\Rightarrow \frac{9}{2}

2\frac{1}{4}\Rightarrow \frac{9}{4}

\text{Jinghua's speed}=\frac{\frac{9}{2}\text{ Miles}}{\frac{9}{4}\text{ Hours}}

Using property \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}:

\text{Jinghua's speed}=\frac{9*4\text{ Miles}}{9*2\text{ Hours}}

\text{Jinghua's speed}=\frac{2\text{ Miles}}{\text{ Hour}}

We know that distance is equal to the product of speed and time.

\text{Distance}=\text{Speed}\times\text{Time}

Since we have been given that Jingua hiked the return trip at the same average rate, so distance covered by her on return trip would be speed (2 miles her hour) times given time (2 1/2 hours).

\text{Distance covered by Jingua on return trip}=\frac{2\text{ Miles}}{\text{ Hour}}\times 2\frac{1}{2}\text{ Hours}

\text{Distance covered by Jingua on return trip}=2\text{ Miles}\times \frac{5}{2}

\text{Distance covered by Jingua on return trip}=5\text{ Miles}

Therefore, Jingua hiked 5 miles on her return trip.

8 0
2 years ago
Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to
nikklg [1K]

Answer:

Part 1)

See Below.

Part 2)

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

Step-by-step explanation:

Part 1)

The linear approximation <em>L</em> for a function <em>f</em> at the point <em>x</em> = <em>a</em> is given by:

\displaystyle L \approx f'(a)(x-a) + f(a)

We want to verify that the expression:

1-36x

Is the linear approximation for the function:

\displaystyle f(x) = \frac{1}{(1+9x)^4}

At <em>x</em> = 0.

So, find f'(x). We can use the chain rule:

\displaystyle f'(x) = -4(1+9x)^{-4-1}\cdot (9)

Simplify. Hence:

\displaystyle f'(x) = -\frac{36}{(1+9x)^{5}}

Then the slope of the linear approximation at <em>x</em> = 0 will be:

\displaystyle f'(1) = -\frac{36}{(1+9(0))^5} = -36

And the value of the function at <em>x</em> = 0 is:

\displaystyle f(0) = \frac{1}{(1+9(0))^4} = 1

Thus, the linear approximation will be:

\displaystyle L = (-36)(x-(0)) + 1 = 1 - 36x

Hence verified.

Part B)

We want to determine the values of <em>x</em> for which the linear approximation <em>L</em> is accurate to within 0.1.

In other words:

\displaystyle \left| f(x) - L(x) \right | \leq 0.1

By definition:

\displaystyle -0.1\leq f(x) - L(x) \leq 0.1

Therefore:

\displaystyle -0.1 \leq \left(\frac{1}{(1+9x)^4} \right) - (1-36x) \leq 0.1

We can solve this by using a graphing calculator. Please refer to the graph shown below.

We can see that the inequality is true (i.e. the graph is between <em>y</em> = 0.1 and <em>y</em> = -0.1) for <em>x</em> values between -0.179 and -0.178 as well as -0.010 and 0.012.

In interval notation:

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

4 0
2 years ago
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