In a linux operating system, which component interprets user commands and forwards them to the os?

1 answer:

6 0

In a Linux system, the shell is a command-line interface that interprets a user's commands and script files, and tells the server's operating system what to do with them. <span> The shell is a program that takes commands from the keyboard and gives them to the operating system to perform.</span>

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A communication pattern in which the parties slowly reduce their dependence on one another, withdraw, and become less invested i

zepelin [54]

Answer:

The correct answer to the following question is option A. an avoidance spiral.

Explanation:

An avoidance spiral is a spiral in which parties avoid the conflicts at all cost in which leads to reducing the influence, dependence, etc. This spiral can also be destructive.

In other words, it is the only spiral in parties slowly reduces their dependence and the influence on the one and another.

7 0

2 years ago

Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi

Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

5 0

2 years ago

Write a function called sum_scores. It should take four arguments, where each argument is the team's score for that quarter. It

saw5 [17]

Answer:

Here is the Python program which has a function sum_scores:

def sum_scores(score1, score2, score3, score4):

sum = score1 + score2 + score3 + score4

print(sum)

sum_scores(14,7,3,0)

Explanation:

Method sum_scores takes four arguments, score1, score2, score3, score4.
The sum variable adds these four scores and stores the value of their addition.
Lastly print statement is used to print the value stored in sum variable which is the value obtained by adding the four scores.
Last statement calls the sum_scores method and passes four values to it which are 14,7,3,0
The output of the above program is:
24
If you want to use return statement instead of print statement you can replace print(sum) with return sum. But in order to display the sum of the scores you can replace sum_scores(14,7,3,0) with print(sum_scores(14,7,3,0))
The program along with the output is attached as a screenshot.