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2 years ago

How do you simplify fractoins

2 answers:

8 0

Find the Greatest Common Factor or GCF of both both fractions and divide.
If the Numerator and the Denominator is both even numbers it is 100% not the simplest form!

VARVARA [1.3K]2 years ago

6 0

Find the GCF of both numerator and denominator and then divide both the denominator and numerator by that and you will get the simplified fraction.

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Set his alarm with a probability of 0.10. If he sets the alarm, it will wake him on time to make his first class with a probabil

Tomtit [17]

Answer:

C) 0.880

B) 0.075

Step-by-step explanation:

If the professor forgets to set the alarm

Probability = 0.1,

Wakes up in time probability = 0.25.

If the professor sets the alarm

Probability = 1 - 0.1 = 0.9

Wake up in time probability = 0.95.

A.)

The probability that professor Moore wakes up in time to make his first class tomorrow

Probability = ( Forgets to set alarm probability x Wakes up in time )+ ( Sets the alarm probability x Wakes up in time ) = ( 0.1 x 0.25 ) + ( 0.9 + 0.95 ) = 0.88

B.)

Late in the class

Set the Alarm Probability = 0.1

Wakes up late probability = 1 - 0.25 = 0.75

Professor Sets the alarm probability = Set the Alarm Probability x Wakes up late probability = 0.1 x 0.75 = 0.075

3 0

2 years ago

The Freeman family is barbecuing veggie burgers, corn cobs, and mushroom caps in their local park. If 3/8of the items barbecued

Inessa05 [86]

Answer:

7/24

Step-by-step explanation:

4 0

2 years ago

The equation 9+12m=6+15(m-1) models the following situation: Movie-rental company A charges a sign-up fee of $9 plus $12 per mon

Ganezh [65]

Answer:

3m = 18

Step-by-step explanation:

9 + 12m = 6 + 15(m - 1)

9 + 12m = 6 + 15m - 15

3m = 18

6 0

2 years ago

Read 2 more answers

A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls invol

bagirrra123 [75]

Answer:

a) 0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b) 0.118 = 11.8% probability that exactly 4 of the calls involve a fax message

c) 0.904 = 90.4% probability that at least 4 of the calls involve a fax message

d) 0.786 = 78.6% probability that more than 4 of the calls involve a fax message

Step-by-step explanation:

For each call, there are only two possible outcomes. Either it involves a fax message, or it does not. The probability of a call involving a fax message is independent of other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

25% of the incoming calls involve fax messages

This means that $p = 0.25$

25 incoming calls.

This means that $n = 25$

a. What is the probability that at most 4 of the calls involve a fax message?

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$ .

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001$

$P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006$

$P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025$

$P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064$

$P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118$

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.001 + 0.006 + 0.025 + 0.064 + 0.118 = 0.214$

0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b. What is the probability that exactly 4 of the calls involve a fax message?

$P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118$

0.118 = 11.8% probability that exactly 4 of the calls involve a fax message.

c. What is the probability that at least 4 of the calls involve a fax message?

Either less than 4 calls involve fax messages, or at least 4 do. The sum of the probabilities of these events is 1. So

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$ . Then

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001$

$P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006$

$P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025$

$P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064$

$P(X$

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.096 = 0.904$

0.904 = 90.4% probability that at least 4 of the calls involve a fax message.

d. What is the probability that more than 4 of the calls involve a fax message?

Very similar to c.

$P(X \leq 4) + P(X > 4) = 1$

From a), $P(X \leq 4) = 0.214)$

Then

$P(X > 4) = 1 - 0.214 = 0.786$

0.786 = 78.6% probability that more than 4 of the calls involve a fax message

8 0

2 years ago

8. The ratio of students in Arts, Science and Commerce Faculties is 5: 4: 3. If the number

N76 [4]

Answer:

Arts=295, Commerce=177

Step-by-step explanation:

That the three subjects have a common ratio implies that there is some common factor between them that relates to the actual number of students in each area, so 5:4:3 means 5x:4x:3x for some value of x

We know that there are 236 science students, so 4x = 236 or x = 59

so the number of arts students is 5(59) and the number of commerce students is 3(59)

Arts = 5*59 = 295

Commerce = 3*59=177

3 0

1 year ago