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katrin2010 [14]
2 years ago
11

PLEASE ANSWER + BRAINLIEST!!! Which graph represents y – 1 = 2(x – 2)?

Mathematics
2 answers:
Varvara68 [4.7K]2 years ago
6 0
Y - 1 = 2(x - 2)
y - 1 = 2x - 4
y = 2x - 4 + 1
y = 2x - 3

So first thing you look for is whichever graph has a y-intercept at y = - 3. Any of the graphs that DON'T have a y-intercept at (0, - 3) can be eliminated. The only one that does is the first graph so... 

Your answer is the first graph. 
GREYUIT [131]2 years ago
6 0
This equation is in point-slope form, which uses the following formula:

y - y_{1} = m(x - x_{1})

x₁ and y₁ represent the values of a point on the graph, and m is the slope of the graph.

This equation has 2 for its x₁ value, and 1 for its y₁ value. Therefore, we are looking for a line that passes through (2,1).

The first graph passes through (2,1). The second, third, and fourth graph do not pass through (2,1). 

The first graph represents y – 1 = 2(x – 2).
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Which statement is true about the equations –3x + 4y = 12 and One-fourthx – One-thirdy = 1?
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Step-by-step explanation:

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In the figure, CD = EF and AB = CE. Complete the statements to prove that AB = DF.
viva [34]

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1. Addition Property of Equality

2. Segment addition

3. Substitution Property of Equality.

4. Transitive Property of Equality.

Step-by-step explanation:

Here, given : CD = EF and AB = CE

To Show:  AB = DF

Now, as given in the steps:

1. CD + DE = EF + DE by the (addition) Property of Equality.

As we have added the EQUAL QUANTITY on both sides of the equality.

2.CE = CD + DE and DF = EF + DE by (segment addition).

As here CE and DF are line segments. And the length of  a

Line Segment = Sum of all its parts in which it is divided.

3.CE = DF by the (Addition, subtraction, substitution, transitive)Property of Equality.

Here, as  we know CE  = CD  + DE

but CD  = EF , so SUBSTITUTE EF in place of CD

⇒ CE = EF + ED  = FD (by substitution) Property of Equality.

4.Given, AB = CE and CE = DF implies AB = DF by the (transitive)Property of Equality.

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Step-by-step explanation: Given that the area of the whole circle is represented by the expression

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We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

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Thus, the area of the outer ring is

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