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irina1246 [14]
2 years ago
13

Nutrition, caregiver responsiveness, and learning opportunities are all __________ influences on maturation. A. environmental B.

hereditary C. sensory D. motor
Physics
2 answers:
yanalaym [24]2 years ago
8 0

Answer:

The answer is A. Environmental.

Explanation:

From diet to moods can affect the environment of the fetus and its growth. The main environmental influences that involve the mother include her nutrition, physical activity, smoking, alcohol intake, drugs, among others. Maturation consists in the development of a sequence of changes and behaviors with a biological basis, where the role of the environment is much more important in the development of personality and intelligence; For example, if parents talk to their children and reward their first sounds by paying attention, smiling or speaking to them, children develop language first.

pentagon [3]2 years ago
6 0

A. Environmental. :)

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Select the correct answer from each drop-down menu.
bagirrra123 [75]

Answer:

(1) An object that’s negatively charged has more electrons than protons.

(2) An object that’s positively charged has fewer electrons than protons.

(3) An object that’s not charged has the same number of electrons than protons.

Explanation :

Objects have three subatomic particles that are Electrons, protons, and neutrons.

Protons and neutrons are found in the nucleus and electrons rotate or move outside the nucleus. Naturally, protons are positively charged, neutrons have no charge, and electrons are negatively charged.

Therefore, an object that is negatively charged has more electrons than protons.  An object that is not charged has the same number of electrons than protons. An object that is positively charged has fewer electrons than protons.

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2 years ago
Two friends, barbara and neil, are out rollerblading. with respect to the ground, barbara is skating due south at a speed of 5.9
Semmy [17]
<span>As seen by Barbara, Neil is traveling at a velocity of 6.1 m/s at and angle of 76.7 degrees north from due west. Let's assume that both Barbara and Neil start out at coordinate (0,0) and skate for exactly 1 second. Where do they end up? Barbara is going due south at 5.9 m/s, so she's at (0,-5.9) Neil is going due west at 1.4 m/s, so he's at (-1.4,0) Now to see Neil's relative motion to Barbara, compute a translation that will place Barbara back at (0,0) and apply that same translation to Neil. Adding (0,5.9) to their coordinates will do this. So the translated coordinates for Neil is now (-1.4, 5.9) and Barbara is at (0,0). The magnitude of Neil's velocity as seen by Barbara is sqrt((-1.4)^2 + 5.9^2) = sqrt(1.96 + 34.81) = sqrt(36.77) = 6.1 m/s The angle of his vector relative to due west will be atan(5.9/1.4) = atan(4.214285714) = 76.7 degrees So as seen by Barbara, Neil is traveling at a velocity of 6.1 m/s at and angle of 76.7 degrees north from due west.</span>
5 0
2 years ago
Read 2 more answers
Your annoying little brother is dropping rocks out of his bedroom window on the 2nd floor. You are on the ground floor and watch
Valentin [98]

Answer:

Too little information, please elaborate

5 0
2 years ago
An 80-kg person stands at one end of a 130-kg boat. He then walks to the other end of the boat so that the boat moves 80 cm with
a_sh-v [17]

Explanation:

We assume that length of boat is L cm. And, we suppose to have a coordinate system relative to the bottom of the lake with:

Boat's position initially from x = 0 cm to x = L cm

Let person (S) is initially at x = L cm (right hand end of boat)

and, let boat's center of mass at x = C cm

Therefore, initially center of mass of overall (system's) is at X_{1} where (taking moments about x = 0).

             (80 + 130)X_{1}

             = 130C + 80L ........... (i)  

After S walks left to the other end of the boat, the boat moves right 80 cm.

Hence,  

Boat's position is now from x = 80 cm to x = (L+ 80) cm

S's position is x = 80 (left end of boat)

Boat's center of mass is at (C + 80).

Therefore, overall (system's) final center of mass is at X_{2} where (taking moments about x = 0).

                (80 + 130)X_{2}

             = (130)(C + 80) + 80 \times 80 ............. (ii)

As no external force is acted on the system, the system's center of mass has not moved, so X_{1} = X_{2}.

This means the left hand sides of both equations (i) and (ii) are equal. So, we can equate the right hand sides giving: the equation as follows.

                130C + 80L = (130)(C+80) + 80 \times 80&#10;

                           80L = 16800 cm

                           L = 210 cm

                             = 2.1 m

Length of boat = 2.1 m

When the person is walking from one end to the other as there was no external force then center of mass of the person-boat system did not move.

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Bad White [126]

Answer:

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