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andrew11 [14]
2 years ago
6

A tuning fork produces a sound with a frequency of 256 hz and a wavelength in air of 1.33 m. find the speed of sound in the vici

nity of the fork.
Physics
1 answer:
aalyn [17]2 years ago
4 0
<span>We can think this through intuitively. A frequency of 256 Hz means that the wave has 256 cycles each second. If the wavelength is 1.33 meters, then there are 256 of them each second. Therefore, we just need to multiply the wavelength by the frequency to find the speed of sound. (Note that the units Hz = 1 / s) v = (frequency) x (wavelength) v = (256 Hz) x (1.33 m) v = 340.5 m/s The speed of sound in the vicinity of the fork is 340.5 m/s</span>
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Calculate the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun
fredd [130]

Answer:

149.34 Giga meter is the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun.

Explanation:

Mass of earth = m = 5.976\times 10^{24} kg

Mass of Sun = M = 333,000 m

Distance between Earth and Sun = r = 149.6 gm =  1.496\times 10^{11} m[/tex]

1 giga meter = 10^{9} meter

Let the mass of the particle be m' which x distance from Sun.

Distance of the particle from Earth = (r-x)

Force between Sun and particle:

F=G\frac{M\times m'}{x^2}=G\frac{333,000 m\times m'}{x^2}

Force between Sun and particle:

F'=G\frac{mm'}{(r-x)^2}

Force on particle is equal:

F = F'

G\frac{333,000 m\times m'}{x^2}=G\frac{mm'}{(r-x)^2}

\frac{x}{r-x}=\sqrt{333,000} = ±577.06

Case 1:

\frac{x}{r-x}=577.06

x = 1.49\times 10^{11} m=149.34 Gm

Acceptable as the particle will lie in between the straight line joining Earth and Sun.

Case 2:

\frac{x}{r-x}=-577.06

x = 1.49\times 10^{11} m=149.86 Gm

Not acceptable as the particle will lie beyond on line extending straight from the Earth and Sun.

3 0
2 years ago
13. An aircraft heads North at 320 km/h rel:
AURORKA [14]

The velocity of the aircraft relative to the ground is 240 km/h North

Explanation:

We can solve this problem by using vector addition. In fact, the velocity of the aircraft relative to the ground is the (vector) sum between the velocity of the aircraft relative to the air and the velocity of the air relative to the ground.

Mathematically:

v' = v + v_a

where

v' is the velocity of the aircraft relative to the ground

v is the velocity of the aircraft relative to the air

v_a is the velocity of the air relative to the ground.

Taking north as positive direction, we have:

v = +320 km/h

v_a = -80 km/h (since the air is moving from North)

Therefore, we find

v'=+320 + (-80) = +240 km/h (north)

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

7 0
2 years ago
A boy of mass 80 kg slides down a vertical pole, and a frictional force of 480 N acts on him. What is his acceleration as he sli
olga_2 [115]

Answer:

His acceleration is \overrightarrow{a}=4\frac{m}{s^{2}}

Explanation:

Newton's second law states that acceleration of a body is cause by a net force, the relation between them is:

\sum\overrightarrow{F}=m\overrightarrow{a}

On the boy there're acting two forces, his weight (W) that points downward and the frictional force (f) that points upward (they boy moves downward and friction always is opposite to movement). So \sum\overrightarrow{F}=\overrightarrow{W}+\overrightarrow{f} so (1) is:

\overrightarrow{W}+\overrightarrow{f}=m\overrightarrow{a}

Using the positive direction downward weight and gravitational acceleration(g) are positive and friction force is negative:

W-f=m\overrightarrow{a}, solving for a:

\overrightarrow{a}=\frac{W-f}{m}, weight is mg:

\overrightarrow{a}=\frac{mg-f}{m}=\overrightarrow{f}=\frac{(80kg)(10\frac{m}{s^{2}})-(480)}{80}

\overrightarrow{a}=4\frac{m}{s^{2}}

6 0
2 years ago
What voltage is required to move 6A through 20?<br><br>​
Marina CMI [18]

Answer:

120V

Explanation:

Given parameters:

Current  = 6A

Resistance  = 20Ω

Unknown:

Voltage = ?

Solution:

According to ohms law;

           V = IR

Where V is the voltage

            I is the current

            R is the resistance

Now, insert the parameters and solve;

    V  = 6 x 20  = 120V

7 0
2 years ago
An airplane travels horizontally at a constant velocity v. An object is dropped from the plane and one second later another obje
Delvig [45]

Answer:

the vertical distance between the two object will increase uniformly when they are dropped after a fixed interval of time

Explanation:

Since airplane is moving horizontally with constant speed v

so when object is dropped from the plane then the speed of the object will be same as that of the speed of the airplane

so we can say that two object when dropped after some interval of time then they always lie in same vertical line

now we know that they both have same acceleration in vertical line so the motion of two objects relative to each other in vertical direction is always uniform motion because they have no acceleration with respect to each other

So the vertical distance between the two object will increase uniformly when they are dropped after a fixed interval of time

8 0
2 years ago
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