Answer:
90.77%
its capacity utilization rate for the month is 90.77%
Explanation:
The capacity utilisation rate can be expressed mathematically as;
Capacity utilisation rate = capacity used/Best operating level × 100%
Given;
Total Number of production time = 205hours
Production output/capacity used = 21400 units
Best operation rate = 115units/hour
Best operation output for the month of July( at best operation level )
=115units/hour × 205 hours = 23575 units
Capacity utilisation rate = 21400/23575 × 100%
= 90.77%
To solve the problem, we enumerate all the given first. Then the required and lastly the solution.
Given:
V1= 1.56x10^3 L = 1560 L P2 = 44.1 kPa
P1 = 98.9 kPa
Required: V2
Solution:
Assuming the gas is ideal. Ideal gas follows Boyle's Law which states that at a given temperature the product of pressure and volume of a gas is constant. In equation,
PV = k
Applying to the problem, we have
P1*V1 = P2*V2
(98.9 kPa)*(1560 L) = (44.1 kPa)*V2
V2 = 3498.5 L
<em>ANSWER: V2 = 3498.5 L</em>
Answer:
d = 3.54 x 10⁴ Km
Explanation:
Given,
The distance between the two objects, r = 2.5 x 10⁴ Km
The gravitational force between them, F = 580 N
The gravitational force between the two objects is given by the formula
F = GMm/r² newton
When the gravitational force becomes half, then the distance between them becomes
Let us multiply the above equation by 1/2 on both sides
( 1/2) F = (1/2) GMm/r²
= GMm/2r²
= GMm/(√2r)²
Therefore, the distance becomes √2d, when the gravitational force between them becomes half
d = √2r = √2 x 2.5 x 10⁴ Km
= 3.54 x 10⁴ Km
Hence, the two objects should be kept at a distance, d = 3.54 x 10⁴ Km so that the gravitational force becomes half.
10,000 units of momentum.
p=mv
20,000=m(2v)
10,000=mv
Answer:4.05 s
Explanation:
Given
First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s
Both hit the ground at the same time
Let h be the height of cliff and it reaches after time t

For second stone
---2
Equating 1 &2 we get




