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Lilit [14]
2 years ago
12

For the Texas Department of Public Safety, you are investigating an accident that occurred early on a foggy morning in a remote

section of the Texas Panhandle. A 2012 Prius traveling due north collided in a highway intersection with a 2013 Dodge Durango that was traveling due east. After the collision, the wreckage of the two vehicles was locked together and skidded across the level ground until it struck a tree. You measure that the tree is 35 ft from the point of impact. The line from the point of impact to the tree is in a direction 39 north of east. From experience, you estimate that the coefficient of kinetic friction between the ground and the wreckage is 0.45. Shortly before the collision, a highway patrolman with a radar gun measured the speed of the Prius to be 50 mph and, according to a witness, the Prius driver made no attempt to slow down. Four people with a total weight of 460 lb were in the Durango. The only person in the Prius was the 150-lb driver. The Durango with its passengers had a weight of 6500 lb, and the Prius with its driver had a weight of 3042 lb.
(a) What was the Durango's speed just before the collision?

(b) How fast was the wreckage traveling just before it struck the tree?
Physics
1 answer:
Bad White [126]2 years ago
5 0

Answer:

JRJJEJERJRJERERJREREJERJJERJERTJE

ExpJERlanation:

SDSHERHJRESHERDHEDGERJEJERJERJERRJERSH

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The standing vertical jump is a good test of an athlete's strength and fitness. The athlete goes into a deep crouch, then extend
SashulF [63]

Answer:

<em>The athlete will rise 1.10 meters off the ground</em>

Explanation:

<u>Vertical Motion</u>

If an object is launched vertically upwards at an initial speed vo, then it will reach a maximum height given by

\displaystyle y_m=\frac{v_o^2}{2g}

The athlete can exert a net force upwards equal to twice his weight. It makes him accelerate upwards at

\displaystyle a=\frac{F_n}{m}=\frac{2W}{m}=2g

The speed at the end of his push can be computed by

v^2=2ay

Replacing the value of a obtained above:

v^2=4gy

where y is the length of this crouch

v^2=4\cdot 9.8\cdot 0.55

v=4.64\ m/s

This is the initial speed of this vertical launch, thus

\displaystyle y_m=\frac{4.64^2}{2\cdot 9.8}

y_m=1.10\ m

5 0
2 years ago
A stiff wire 50.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l
zloy xaker [14]

Answer:

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

Explanation:

The stiff wire 50.0cm long bent at a right angle in the middle

One section lies along the z axis and the other is along the line y=2x in the xy plane

\frac{y}{x} = 2

tan θ = 2

Therefore,

slope m = tan θ = y / x

\theta=\tan^-^1(2)=63.4^0

Then length of each section is 25.0cm

so, length vector of the wire is

\hat I= (-25.0)\hat k +(25.0) \cos 63.4^0 \hati +(25.0) \sin63.4^0 \hatJ\\\\\hat I = (11.2) \hat i + (22.4) \hat j - (23.0) \hat k

And magnetic field is B = (0.318T)i

Therefore,

\bar F = \hat I (\bar l \times \bar B)

\bar F = (20.0)[(0.112m)i +(0.224m)j-(0.250m)k \times 90.318T)i]

= (20.0)(i(0)+j(-0.250)(0.318T)+k[0-(0.224m)(0.318T)]\\\\=(20.0)(-0.250)(0.318)j-(20.0)(0.224)(0.318T)\\\\=-(1.59N)j-(1.425N)k

Magnitude of the force is

F = \sqrt{(-1.59N)^2+(-1.425N)^2\\} \\F = 2.135N

Direction is

\alpha = \tan^-^1(\frac{-1.425N}{-1.59N} )\\\\= 41.8^0

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

5 0
2 years ago
Read 2 more answers
A runner runs 300 m at an average speed of 3.0 m/s. She then runs another 300m at an average
Kaylis [27]

Answer:

B. 4 m/s

Explanation:

v=d/t

Running for 300 m at 3 m/s takes 100 seconds and running at 300 m at 6 m/s takes 50 seconds. 100 s + 50 s = 150 s (total time). Total distance is 600 m, so 600 m/ 150 s = 4 m/s.

3 0
2 years ago
Neha and Suhani are playing with two identical pendulums. They leave the bob from a certain position and wait for it to return t
Anika [276]

Answer:

The correct option is C

Explanation:

The pendulum bob would return at the same time because the initial angle a pendulum bob is dropped does not affect it's period (the time it takes for the pendulum to move back and forth), however the one with a larger angle move faster but would eventually arrive at the same "starting point" due to varying displacements made.

6 0
2 years ago
(8%) Problem 9: Helium is a very important element for both industrial and research applications. In its gas form it can be used
exis [7]

Answer:

2046.37 kPa

Explanation:

Given:

Number of moles, n = 125

Temperature, T = 20° C = 20 + 273 = 293 K

Radius of the cylinder, r = 17 cm = 0.17 m

Height of the cylinder, h = 1.64 m

thus,

volume of the cylinder, V = πr²h

= π × 0.17² × 1.64

= 0.148 m³

Now,

From the ideal gas law

we have

PV = nRT

here,

P is the pressure

R is the ideal gas constant = 8.314  J / mol. K

thus,

P × 0.148 = 125 × 8.314 × 293

or

P × 0.148 = 304500.25

or

P = 2046372.64 Pa = 2046.37 kPa

6 0
2 years ago
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