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TiliK225 [7]
2 years ago
6

Bill leaves his 60 W desk lamp on every day, including weekends, for eight hours. After one month (30 days), how much total ener

gy has been used by the lamp? Round your answer to the nearest whole number. kWh
Physics
1 answer:
maxonik [38]2 years ago
7 0

' W ' is the symbol for 'Watt' ... the unit of power equal to 1 joule/second.

That's all the physics we need to know to answer this question.
The rest is just arithmetic.

(60 joules/sec) · (30 days) · (8 hours/day) · (3600 sec/hour)

= (60 · 30 · 8 · 3600) (joule · day · hour · sec) / (sec · day · hour)

= 51,840,000 joules
__________________________________

Wait a minute !  Hold up !  Hee haw !  Whoa ! 
Excuse me.  That will never do.
I see they want the answer in units of kilowatt-hours (kWh).
In that case, it's

(60 watts) · (30 days) · (8 hours/day) · (1 kW/1,000 watts)

= (60 · 30 · 8 · 1 / 1,000) (watt · day · hour · kW / day · watt)

= 14.4 kW·hour

Rounded to the nearest whole number:

14 kWh

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FromTheMoon [43]

Answer:\alpha =30-4=26 rad/s^2

Explanation:

Given

Position of a car is  given by

\theta =t^3-2t^2-4t+10

and angular speed is \frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

angular acceleration is

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha

\alpha =6t-4

at t=5 s

\alpha =30-4=26 rad/s^2

4 0
2 years ago
A hot air balloon must be designed to support a basket, cords, and one person for a total payload weight of 1300 N plus the addi
RSB [31]

Answer:

r = 4.44 m

Explanation:

 

For this exercise we use the Archimedes principle, which states that the buoyant force is equal to the weight of the dislodged fluid

         B = ρ g V

Now let's use Newton's equilibrium relationship

         B - W = 0

         B = W

The weight of the system is the weight of the man and his accessories (W₁) plus the material weight of the ball (W)

         σ = W / A

         W = σ A

The area of ​​a sphere is

           A = 4π r²

       W = W₁ + σ 4π r²

The volume of a sphere is

           V = 4/3 π r³

Let's replace

     ρ g 4/3 π r³ = W₁ + σ 4π r²

If we use the ideal gas equation

     P V = n RT

    P = ρ RT

    ρ = P / RT

 

    P / RT g 4/3 π r³ - σ 4 π r² = W₁

    r² 4π (P/3RT  r - σ) = W₁

Let's replace the values

     r² 4π (1.01 10⁵ / (3 8.314 (70 + 273)) r - 0.060) = 13000

     r² (11.81 r -0.060) = 13000 / 4pi

     r² (11.81 r - 0.060) = 1034.51

As the independent term is very small we can despise it, to find the solution

       r = 4.44 m

3 0
2 years ago
Four students measured the acceleration of gravity. The accepted value for their location is 9.78 m/s2. Which student's measurem
garri49 [273]
<span>the answer would actually be student 1 :9.87 m/s2, not 9.78</span>
6 0
2 years ago
Read 2 more answers
Reginald slipped and broke his leg in his kitchen when he ran inside to grab a cookie. His mother had just mopped the floor. Wha
padilas [110]

Answer:

A. <u>The water decreases the friction between the floor and the feet </u>

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3 0
2 years ago
A 0.110 kg cube of ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.70
Sonbull [250]

Answer:

the distance by which the height of the  liquid in the cylinder change after the ice gets melted = 0.528 cm

Explanation:

The change in volume of glycerin when the ice cube is placed on the surface of the glycerin can be represented as:

V = \frac{m}{ \rho}

Given that ;

the mass of the ice cube (m) = 0.11 kg = 0.110 × 10³ g

density of the glycerine (\rho) = 1.260 kg/L = 1.260 g/cm³

Then:

V = \frac{0.110*10^3 \ g}{1.260 \ g/cm^3}

V = 0.0873*10^3 \ cm^3 (\frac{1L}{10^3 cm^3})

V = 0.0873 L

Now;Initially the volume of the glycerin before the ice cube starts to melt is:

V_1 = V_i + V\\\\V_1 = V_i+ 0.0873 \ L

However; the volume of the water produced by the 0.11 kg ice cube = 0.11*10^3 \ cm^3

The expression for change in the volume of glycerin after the ice cube starts to melt is as follows:

V_2 = V_i + V"

replacing V" with 0.11*10^3 \ cm^3 ; we have:

V_2 = V_i (0.11*10^3 \ cm^3 )(\frac{1 \ L }{10^3 \ cm^3})

V_2 = V_i + 0.11 \ L

The overall total change in the volume of the glycerin is illustrated as:

V_f = V_2 - V_1

Now; from the foregoing ; lets replace the respective value of V_2 and V_1 in the above equation ; we have;

V_f = (V_i + 0.11 \ L) - (V_i + \ 00873 \ L)\\ \\V_f = 0.11 L - 0.0873 \ L\\\\V_f = 0.0227 \ L

The formula usually known to be the volume of a cylinder is :

V = \pi r ^2 h

For the question ; we will have:

V_f = \pi r ^2 h

making h the subject of the  formula ; we have:

h = \frac{V_f}{\pi r^2}

replacing 0.0227 L for V_fand the given value of radius which is = 3.70 cm; we have:

h = \frac{0.0227 \ L ( \frac{10^3 \ cm^3}{1\ L})}{\pi * (3.70 cm)^2}

h = \frac{22.7 \ cm^3}{\pi * (3.70 cm)^2}\\\\h = 0.528 \ \ cm

Thus ; the distance by which the height of the  liquid in the cylinder change after the ice gets melted = 0.528 cm

8 0
2 years ago
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