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JulsSmile [24]
2 years ago
12

Line jk passes through points j(-4,-5) and k(-6,3 if the equation of the lines is written in slope-intercept form,y=my+b what is

the value of b?

Mathematics
1 answer:
lidiya [134]2 years ago
6 0
Written in 2-point form, the equation of the line is
  y = (y2-y1)/(x2-x1)·(x-x1) +y1
  y = (3-(-5))/(-6-(-4))·(x-(-4)) + (-5)
  y = 8/-2·(x +4) - 5
  y = -4x -21

The value of b is -21.

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bagirrra123 [75]

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Step-by-step explanation:

Coordinates of the ends of a line MN → M(-3, 5) and N(2, 0)

Slope of a line = \frac{y_2-y_1}{x_2-x_1}

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