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nadya68 [22]
2 years ago
15

Maël mixes 15 milliliter (mL) of bleach with 3.75 liters (L) of water to make a sanitizing solution for a daycare. The amounts o

f bleach and water always have to be proportional when he makes sanitizing solution. Which of the following could be combinations of volumes of bleach and water for Maël's sanitizing solution?
Mathematics
1 answer:
Yanka [14]2 years ago
5 0
You have not provided the options, therefore, I cannot give you an exact answer.
However, I will try to help you with the concept.

<u>First, we need to make all units the same in the problem. I will convert all units to ml.</u>
We have:
amount of bleach = 15 ml
amount of water = 3.75 liters = 3.75 * 1000 = 3750 ml

<u>Now, we will get the ratio between bleach and water:</u>
\frac{bleach}{water} =  \frac{15}{3750} =  \frac{1}{250}

<u>This ratio is fixed, therefore, to get the right choice:</u>
1- make all units the same
2- for each option, divide the amount of bleach by the amount of water.
The correct choice would be the one giving you \frac{1}{250}

Hope this helps :)
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Triangle H N K is shown. Angle H N K is 90 degrees. The length of hypotenuse H K is n, the length of H N is 12, and the length o
Mazyrski [523]

Answer:

13

Step-by-step explanation:

From the question, we are given a triangle HNK with an angle of 90°

The length of hypotenuse H K is n,

the length of HN is 12

the length of N K is 6.

From the above values, obtained in the question, we can see that this is a right angled triangle.

We are asked to find the length of the hypotenuse.

We can use Pythagoras Theorem of solve for this.

c² = a² + b²

where c = HK = n

a = NK = 6

b = HN = 12

c² = 6² + 12²

c² = 36 + 144

c² = 180

c = √180

c = 13.416407865

Approximately to the nearest whole number = 13

Therefore the value of HK = n = 13

We can also use Law of Cosines as given in the question to solve for this.

a² = b² + c² - 2ac × Cos A

where c = HK = n

a = NK = 6

b = HN = 12

Hence

c² = a² + b² - 2ab × Cos C

c = √ (a² + b² - 2ab × Cos C)

Where C = 90

c = √ 6² + 12² - 2 × 6 × 12 × Cos 90

c = 13.42

Approximately to the nearest whole number ≈ 13

Therefore the value of HK = n = 13

8 0
2 years ago
A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r
eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

            Radius= 1.5 m

            Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= 2\pi rh

Considering, π= 3.14

⇒ lateral surface area of cylinder= 2\times 3.14\times 1.5\times 2.5

⇒ lateral surface area of cylinder= 23.55 \ m^{2}

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= \frac{16500}{23.55} = 700.6369 \approx 701

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

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2 years ago
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