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nadya68 [22]
2 years ago
15

Maël mixes 15 milliliter (mL) of bleach with 3.75 liters (L) of water to make a sanitizing solution for a daycare. The amounts o

f bleach and water always have to be proportional when he makes sanitizing solution. Which of the following could be combinations of volumes of bleach and water for Maël's sanitizing solution?
Mathematics
1 answer:
Yanka [14]2 years ago
5 0
You have not provided the options, therefore, I cannot give you an exact answer.
However, I will try to help you with the concept.

<u>First, we need to make all units the same in the problem. I will convert all units to ml.</u>
We have:
amount of bleach = 15 ml
amount of water = 3.75 liters = 3.75 * 1000 = 3750 ml

<u>Now, we will get the ratio between bleach and water:</u>
\frac{bleach}{water} =  \frac{15}{3750} =  \frac{1}{250}

<u>This ratio is fixed, therefore, to get the right choice:</u>
1- make all units the same
2- for each option, divide the amount of bleach by the amount of water.
The correct choice would be the one giving you \frac{1}{250}

Hope this helps :)
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1 year ago
A large manufacturing plant has analyzed the amount of time required to produce an electrical part and determined that the times
WARRIOR [948]

Answer:

We conclude that the new procedure will not decrease the population mean amount of time required to produce the part.

Step-by-step explanation:

We are given that a large manufacturing plant has analyzed the amount of time required to produce an electrical part and determined that the times follow a normal distribution with mean time μ = 45 hours.

A random sample of 25 parts will be selected and the average amount of time required to produce them will be determined. The sample mean amount of time is = 43.118 hours with the sample standard deviation s = 5.5 hours

<em>Let </em>\mu<em> = population mean amount of time required to produce an electrical part using new procedure</em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \geq  45 hours   {means that the new procedure will remain same or increase the population mean amount of time required to produce the part}

<u>Alternate Hypothesis,</u> H_a : \mu < 45 hours   {means that the new procedure will decrease the population mean amount of time required to produce the part}

The test statistics that will be used here is <u>One-sample t test statistics </u>because we don't know about the population standard deviation;

              T.S.  = \frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }  ~ t_n_-_1

where,  \mu = sample mean amount of time = 43.118 hours

             s = sample standard deviation = 5.5 hours

             n = sample of parts = 25

So, <u><em>test statistics</em></u>  =  \frac{43.118-45}{{\frac{5.5}{\sqrt{25} } } }  ~ t_2_4

                               =  -1.711

<em>Now at 0.025 significance level, the t table gives critical value of -2.064 at 24 degree of freedom for left-tailed test. Since our test statistics is more than the critical value of t so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the new procedure will remain same or increase the population mean amount of time required to produce the part.

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1 year ago
The size of angle aob is equal to 132 degrees and the size of angle cod is equal to 141 degrees. find the size of angle dob.
Varvara68 [4.7K]

angle AOB = 132 and is also the sum of angles AOD and DOB. Hence 
angle AOD + angle DOB = 132°    ---> 1 

angle COD = 141 and is also the sum of angles COB and BOD. Hence 
angle COB + angle DOB = 141°    ---> 2

Now we add the left sides together and the right sides of equations 1 and 2 together to form a new equation. 

angle AOD + angle DOB + angle COB + angle DOB = 132 + 141       ---> 3 

We should also note that: 
angle AOD + angle DOB + angle COB = 180° 

Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180 and solving for angle DOB:
180 + angle DOB = 132 + 141 
angle DOB = 273 - 180 = 93° 

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