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2 years ago

f a laptop originally costs $800, the balance due after the 10% discount and $150 gift card is applied is $ .

Mathematics

1 answer:

pav-90 [236]2 years ago

6 0

The 10% discount is $80 plus $150 gift card equals $230
$800- $230= $570

$570 is your answer
hope this helps!

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Answer Please???? Finn is baking cakes for a party. The number of cups of sugar Finn needs is proportional to the number of cake

Natali [406]

Answer:

Hello there!

The answer to your question is :

C: Finn needs 6 cups of sugar for 4 cakes.

D: Finn needs 1 1/2 cups of sugar for 1 cake.

Step-by-step explanation:

The graph clearly shows ( sides cups of sugar) (bottom number of cakes)

For sugar you need 6 cups to make 4 cakes

For sugar on the second question you need 1 1/2 cups of sugar to make 1 cake

Multiply 1 1/2 times 6 then divide and your answer is 4. That's 4 cakes out of 6 cups of sugar out of the original cups of sugar ( 1 1/2)

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What is the slope of the line through ( − 5 , − 10 ) (−5,−10)left parenthesis, minus, 5, comma, minus, 10, right parenthesis and

nikdorinn [45]

Answer:

3.75

Step-by-step explanation:

We have to find the slope of a straight line through points (-5,-10) and (-1,5).

Now. we know the slope of a straight line through the points ( $x_{1},y_{1}$ ) and ( $x_{2},y_{2}$ ) is given by $[\frac{y_{2} - y_{1} }{x_{2} - x_{1}} ]$ .

So, in our case ( $x_{1},y_{1}$ ) ≡ (-5,-10) and ( $x_{2},y_{2}$ ) ≡ (-1,5).

Therefore, the slope of the line is $\frac{5 - (- 10)}{- 1 - (- 5)} = \frac{15}{4} = 3.75$ (Answer)

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2 years ago

Given: 3AB = 7AD and 3AC = 7AE Prove: ΔABC ~ ΔADE Triangles A B C and A E D are connected at point A. Complete the steps of the

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2 years ago

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Conservation of Species A certain species of turtle faces extinction because dealers collect truckloads of turtle eggs to be sol

JulijaS [17]

Answer:

The turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.

Ten years after the conservation measures are implemented the population will be 3260 turtles.

Step-by-step explanation:

To find the rate of growth of the turtle population at any time t you need to find $N'(t)$

$\frac{d}{dt}N(t)=\frac{d}{dt}(2t^3+3t^2-4t+1000)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\\frac{d}{dt}(2t^3)+\frac{d}{dt}(3t^2)-\frac{d}{dt}(4t)+\frac{d}{dt}(1000)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\N'(t)=6t^2+6t-4$

In particular, when t = 2 and t = 6, we have

$N'(2)=6(2)^2+6(2)-4=32\\\\N'(6)=6(6)^2+6(6)-4=248$

so the turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.

The turtle population at the end of the tenth year will be

$N(10)=2(10)^3+3(10)^2-4(10)+1000\\N(10)=3260 \:turtles$

3 0

2 years ago