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2 years ago

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Given: 3AB = 7AD and 3AC = 7AE Prove: ΔABC ~ ΔADE Triangles A B C and A E D are connected at point A. Complete the steps of the

proof. ♣: ♦:

2 answers:

galben [10]2 years ago

6 0

Answer:

division property & SAS

Step-by-step explanation:

Effectus [21]2 years ago

4 0

Want me to still send the answer or later?

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In a golf tournament, Sam played 4 rounds and was within 2 strokes of par for all 4 rounds of the tournament. If par is 72 on th

In-s [12.5K]

Given:

$|x-4(72)|=2$

To find:

The highest and lowest scores Sam could have made in the tournament.

Solution:

We have,

$|x-4(72)|=2$

$|x-288|=2$

It can be written as

$x-288=\pm 2$

Add 288 on both sides.

$x=288\pm 2$

$x=288-2$ and $x=288+2$

$x=286$ and $x=290$

Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.

8 0

2 years ago

Write three to five sentences explaining which levels of production provide Alonzo’s Cycling with the maximum profit.

denis-greek [22]

Answer:

The maximum profit can be attained when 4 bikes are produced each day.

Step-by-step explanation:

Look at the attached picture:

In the table given in the picture, the number of bikes produces varies. We cannot properly compare the profits per day. To be consistent, let us determine the profit per unit of bike produced.The relationship between cost, revenue and profit can be as:

Profit = Revenue - Cost

To find the profit per unit of bike, simply divide the profit with the number of bikes produced (1st column). After you see the results, we can see that the highest profit is $17.5 per unit of bike produced. Therefore, the maximum profit can be attained when 4 bikes are produced each day.

7 0

2 years ago

Read 2 more answers

Complete the steps for solving 7 = –2x2 + 10x. Factor out of the variable terms. inside the parentheses and on the left side of

Mamont248 [21]

we have

$7=-2x^{2} +10x$

Factor the leading coefficient

$7=-2(x^{2} -5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$7-12.50=-2(x^{2} -5x+2.5^{2})$

$-5.50=-2(x^{2} -5x+2.5^{2})$

Divide both sides by $-2$

$2.75=(x^{2} -5x+2.5^{2})$

Rewrite as perfect squares

$2.75=(x-2.5)^{2}$

Taking the square roots of both sides (square root property of equality)

$x-2.5=(+/-)\sqrt{2.75}$

Remember that

$\sqrt{2.75}=\sqrt{\frac{11}{4}}= \frac{\sqrt{11}}{2}$

$x-2.5=(+/-)\frac{\sqrt{11}}{2}$

$x=2.5(+/-)\frac{\sqrt{11}}{2}$

$x=2.5+\frac{\sqrt{11}}{2}=\frac{5+\sqrt{11}}{2}$

$x=2.5-\frac{\sqrt{11}}{2}=\frac{5-\sqrt{11}}{2}$

<u>the answer is</u>

The solutions are

$x=\frac{5+\sqrt{11}}{2}$

$x=\frac{5-\sqrt{11}}{2}$

5 0

2 years ago

Read 2 more answers

Katherine is landscaping her home with juniper trees and pansies. She wants to arrange 15 pansies around each of 8 trees. Each t

Doss [256]

Let
X-----------------> number of pansies
y-----------------> number of trees

we know that
x=15*8----------> x=120 pansies
y=8 trees

cost of each trees is----------> $<span>20.75
</span>cost of each pansies is------> $2.50/6------> $5/12

[<span>expression to find Katherine’s final cost]=[cost trees]+[cost pansies]
</span>[cost trees]=y*$20.75
[cost pansies]=x*($5/12)

[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)

[expression to find Katherine’s final cost]=$166+$50
[expression to find Katherine’s final cost]=$216

the answer is
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)

Katherine’s final cost is $216

5 0

2 years ago

Read 2 more answers

This semester, the tuition fee increased to $5,871. If this represents an increase by 14%, what was the original fee?

MissTica

Use a calculator its easy

7 0

1 year ago