For this case we have the following equation:
y = 3619000 (2.7) ^ 0.009t
We must evaluate the equation for the year 2000.
Therefore, we must replace the following value of t:
t = 2000 - 1994
t = 6
Substituting we have:
y = 3619000 (2.7) ^ (0.009 * 6)
y = 3818407.078
Round to the nearest ten thousand:
y = 3820000
Answer:
3820000 residents are living in that city in 2000
Your answer is E. $25.
First let under 12 = u, over 12 = o, and adults = a.
We can now write the equations:
2u + 3a + 3o = 174
4u + 2a = 122
a + o = 46
Because we know that a + o = 46, and 3a + 3o is in the first equation, we can multiply 46 by 3 to get what 3a + 3o equals. This makes 138.
Now we can substitute 138 into the first equation to get 2u + 138 = 174
2u = 36
u = 18
Now that we know what u equals, we can substitute it in to the second equation to get:
4(18) + 2a = 122
72 + 2a = 122
2a = 50
a = $25
I hope this helps! Let me know if you have any questions :)
Answer: 1.B 2.C 3.A 4.d
Step-by-step explanation:
Area = perimeter + 132.
Let each side of the city be x miles long, then:-
x^2 = 4x + 132
x^2 - 4x - 132 = 0
x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2
x = 13.66, -9.66 We ignore the negative
So the city has dimension of 13.66 * 13.66
13.7 * 13.7 to nearest 10th
