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Makovka662 [10]
2 years ago
8

Jenn will use 18 connecting cubes to make a model of a park. The model will be in the shape of a rectangle and will have a heigh

t of one cube. In how many different ways can Jenn make the model of the park?
Mathematics
1 answer:
Margarita [4]2 years ago
3 0
This question is basically: how many different pairs of numbers multiply up to 18?

(This is a simpler form of the question because the question is just asking how many shapes of a rectangle can Jenn create with 18 blocks)

So, the numbers that multiply up to 18 are:

1 x 18
2 x 9
3 x 6

So, the answer is: Jenn can make the model of the park in 3 different ways.
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Ming writes a number pattern on a slip of paper and hands it to his friend Jack. 24 21 23 20 22 19 21 18 Jack writes the next nu
tiny-mole [99]
The rule is -3, then +2

24-3 = 21
21 + 2 = 23
23-3= 20
20+2= 22
22-3= 19
19+2 = 21
21-3= 18
18+2 = 20
3 0
1 year ago
En una cancha se va a pintar la circunferencia central que tiene un diámetro de 5 m .¿cual es la longitud de la circunferencia?
Alona [7]

Answer:

The length of the circumference is 5\pi\ m  or 15.70\ m

Step-by-step explanation:

<u><em>The question in English is</em></u>

On a court, the central circumference will be painted, which has a diameter of 5 m. What is the length of the circumference?

we know that

The circumference of a circle is given by the formula

C=\pi D

we have

D=5\ m

substitute

C=\pi (5)\\C=5\pi\ m

This is the exact value

assume

\pi=3.24

C=5(3.14)=15.70\ m

4 0
1 year ago
Adam plans to choose a video game from a section of the store where everything is 75 % off . He writes the expression d - 0.75d
masha68 [24]

Answer:

Adam is taking the original price minus 75% of the original price, while Rena is taking the original price times 25% which is what you would be paying. Both are correct but Renas is more efficient.

Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes"† proposed using the Poisson distribution
oksian1 [2.3K]

Answer:

a. P(X ≤ 5) = 0.999

b. P(X > λ+λ) = P(X > 2) = 0.080

Step-by-step explanation:

We model this randome variable with a Poisson distribution, with parameter λ=1.

We have to calculate, using this distribution, P(X ≤ 5).

The probability of k pipeline failures can be calculated with the following equation:

P(k)=\lambda^{k} \cdot e^{-\lambda}/k!=1^{k} \cdot e^{-1}/k!=e^{-1}/k!

Then, we can calculate P(X ≤ 5) as:

P(X\leq5)=P(0)+P(1)+P(2)+P(4)+P(5)\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\P(3)=1^{3} \cdot e^{-1}/3!=1*0.3679/6=0.061\\\\P(4)=1^{4} \cdot e^{-1}/4!=1*0.3679/24=0.015\\\\P(5)=1^{5} \cdot e^{-1}/5!=1*0.3679/120=0.003\\\\\\P(X\leq5)=0.368+0.368+0.184+0.061+0.015+0.003=0.999

The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:

P(X>2)=1-(P(0)+P(1)+P(2))\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\\\P(X>2)=1-(0.368+0.368+0.184)=1-0.920=0.080

4 0
2 years ago
While standing on a highway overpass, Jennifer wonders what proportion of the vehicles that pass on the highway below are trucks
Assoli18 [71]

Answer:Obtain a systematic sample by selecting every 20th vehicle that passes (in any lane and going in any direction).

Step-by-step explanation:

8 0
2 years ago
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