
8 out of 300 were defective.
80 pairs were defective
Answer:
a) density of the object is 3995.01, b) the weight scale reads 22N c) the sum individually will be the same with when added together.
Step-by-step explanation:
The weight of the object in air is 8N,
and weight = Mass * acceleration due to gravity = m * 9.81
8/9.81 = 0.815,
upthrust( force acting on the body from the liquid impeding the immersion) on the body when fully submerged = weight in air - weight in water = 8N - 6N =2N
Upthrust = weight of water displaced = 2N = mass * acceleration
2/9.81 = 0.204kg
density of water(1000kg/m^3) = mass of water / volume of water
volume of water displaced = 0.204/1000 = 0.000204m^3 (204cm^3)
volume of water displaced = volume of the solid
density of solid = mass/ volume = 0.815/0.000204 = 3995.01kg/m^3
b) when fully submerge in water the the scale experience according to newton third law of motion ( equal and opposite reaction of forces) additional 2N push so that total weight with the fully submerge solid = 20N + upthrust = 20N + 2N =22N
c) the of two scale reading is before (8N + 20N = 28N) and after (6N + 22N = 28) since there is no loss of matter; the demonstration was in equilibrium.
A. True. There are 52 cards total and you only pick 5. Order doesn't matter.
-------------------------------------------
B. False. Order doesn't matter so you use a combination (instead of a permutation) as choice A shows.
-------------------------------------------
C. False. The answer is roughly 0.000858 as shown by the calculation below
(13/52)*(12/51)*(13/50)*(12/49)*(11/48) = 0.000858
-------------------------------------------
D. False. See calculation below
(13/52)*(12/51)*(11/50)*(10/49)*(9/48) = 0.000495
-------------------------------------------
E. True. See calculation below
(13/52)*(12/51)*(11/50)*(10/49)*(9/48) = 0.000495
this value rounds to roughly 0.0005
Problem: If you and your friend paid the same amount for the, same number of megabytes, How many megabytes did you each use?
<span>
Given facts: company 1 (mine)
$0.10 per megabyte
$10 flat fee
Company 2 (friend)
$0.25 per megabyte
no flat fee.
method: division
Solution: Company 1 Company 2
</span>$ <span>0.10 = 1 megabyte $ 0.25 = 1 megabyte
</span> $10/ $0.10 = 100 megabytes $ 10/$0.25= 40 megabytes
(* using $10 as same payment for both)
Answer: Company 1 Company 2
for $10 = 100 megabytes $ 10= 40 megabytes