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EastWind [94]
2 years ago
5

Victoria has a 2 pound package of flour. She uses 2/5 of the flour to make pizza. She then uses 3/10 of the remaining flour to m

ake bread. Find the weight of the package of flour that she has left. Express your answer as a decimal.
Mathematics
1 answer:
timama [110]2 years ago
7 0
One pound= 16 ounces 

2 x 16 = 32 ounces = 2 pounds

2/5 can also be expressed in decimal form as .4

so 32 x .4 = 12.8

and then 3/10 also is .3 

so 32 x .3 = 9.6 

add the two 12.8 + 9.6 = 22.4

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each morning papa notes the birds feeding on his birdfeeder. so far this month he has seen 59 blue jays, 68 black crows, 12 red
Vitek1552 [10]
It think it's 59/81.
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Jack bought a car for $17,500. The car loses $750 in value each year. Which equation represents the situation? Question 9 option
yuradex [85]
If im understanding this correctly, to find the value of the car after x amount of years, the answer would be 17,500 - 750(x)
5 0
1 year ago
Read 2 more answers
Given that $A = (\sqrt{2008}+\sqrt{2009}),$ $B = (-\sqrt{2008}-\sqrt{2009}),$ $C = (\sqrt{2008}-\sqrt{2009}),$ and $D = (\sqrt{2
kipiarov [429]

Answer:

ABCD = 0.803

Step-by-step explanation:

A = \sqrt{2008}+\sqrt{2009} \\A = 44.81 + 44.82\\A = 89.63

B = -\sqrt{2008}-\sqrt{2009}\\B = -44.81 - 44.82\\B = -89.63

C = \sqrt{2008}-\sqrt{2009}\\C = 44.81 - 44.82\\C = - 0.01

D = \sqrt{2009}-\sqrt{2008}\\D = 44.82 - 44.81\\D = 0.01

ABCD = 89.63 * (-89.63) * (-0.01) * (0.01)

ABCD = 0.803

6 0
2 years ago
For the dilation, DO, K = (10, 0) → (5, 0), the scale factor is equal to _____.
eduard
Scale factor is equal to 1/2, since the point went from 10 to 5
6 0
2 years ago
Read 2 more answers
Jack was so frustrated with his slow laptop that he threw it out of his second story window. The height, h, of the laptop at tim
jeyben [28]

Answer:

The domain of the function is the interval [0,2.23]

see the explanation

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> the height of the laptop in units

we have

h(t)=-16t^{2}+28t+17

we know that

When the laptop hits the ground, the value of h(t) is equal to zero

so

For h(t)=0

-16t^{2}+28t+17=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+28t+17=0

so

a=-16\\b=28\\c=17

substitute in the formula

x=\frac{-28(+/-)\sqrt{28^{2}-4(-16)(17)}} {2(-16)}

x=\frac{-28(+/-)\sqrt{1,872}} {-32}

x=\frac{-28(+/-)12\sqrt{13}} {-32}

x_1=\frac{-28(+)12\sqrt{13}} {-32}=-0.477

x_1=\frac{28(-)12\sqrt{13}} {32}=-0.477  ---> is not a solution

x_2=\frac{-28(-)12\sqrt{13}} {-32}

x_2=\frac{28(+)12\sqrt{13}} {32}=2.23\ sec

therefore

The domain of the function is the interval [0,2.23]

All real numbers greater than or equal to 0 seconds and less than or equal to 2.23 seconds

0\ sec \leq x \leq 2.23\ sec

5 0
2 years ago
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