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storchak [24]
2 years ago
3

Brett currently spends $160 each month on gas. His current car is able to travel 30 miles per gallon of gas. He decides to switc

h his current car for a new car that is able to travel 40 miles per gallon of gas. Assuming the price of gas stays the same, how much will he spend on gas each month with the new car?
Mathematics
1 answer:
lesya692 [45]2 years ago
4 0

As per the problem

Brett currently spends $160 each month on gas.

Brett current car is able to travel 30 miles per gallon of gas.

New car is able to travel 40 miles per gallon of gas.

Assuming the price of gas stays the same.

It mean that the cost when car is able to travel 40 miles per gallon of gas can be given by

Cost=\frac{30}{40}*160   \ dollar \\ \\ Cost= 30*4 \ dollar\\ \\ Cost=120 \ dollar \\

Spend on gas each month with the new car=$120.

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Answer:

a. 205320

b. 34220

c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!

Step-by-step explanation:

a) The number of ways to dustribute exams among the TA's is:

n / (n - r)!

n= number of things to choose from

r= Choosing r number

60P3= 60! / (60 - 3)!

(60)(59)(58)(57)! / (57)!

=205320

B) The number of ways to dustribute the exams among the TA's is:

n! /(n - r)! r!

60C3= 60! /(60 - 3)! 3!

= 60!/ 57! 3!

= 60 × 59 × 58 / 3 × 2 × 1

= 34220

C) The required number of ways is:

60C25 + 60C20 + 60C15

= 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!

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2 years ago
9,290 is the value of the first 9 ten times as great as the value of the second 9?
Semenov [28]

Answer:

No

Step-by-step explanation:

The first nine in on the place of the thousands, while the second nine is on the place of the tens. so the first nine is a hundred times as great as the second nine

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2 years ago
Really important please help #8
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One min after it ends
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How do you solve -9( -4r + 6s ) + 3s - 7(6s - 2r)
slavikrds [6]

Answer: 2.1 Pull out like factors :

6s - 2r  =   -2 • (r - 3s)

Equation at the end of step

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Pulling out like terms

4.1     Pull out like factors :  6s - 4r  =   -2 • (2r - 3s)

Equation at the end of step

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Final result :

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