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2 years ago

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Me awaari brought 2/3 of rice pudding to a pot luck dinner the group at the dinner ate 3/4 of what me awaari brought how much of

the original tray of rice was eating at the pot luck dinner
A 3/4
B1/2
C 1/3
D 1/4

1 answer:

Nadya [2.5K]2 years ago

7 0

I think it’s a) 3/4

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14. A $40,000 loan at 4% dated June 10 is due to be paid on October 11. Calculate the amount of interest (assume ordinary intere

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D) $546.67

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Consider the diagram.<br> What is QS?<br> 2 units<br> 5 units<br> 17 units<br> 33 units

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The answer on ed is 17 units I took the test.

Step-by-step explanation:

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A scuba diver is descending at an average rate of 44.5 feet per minute.

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Scuba diver has done 102.35 feet below sea level.

The diver is:

descending at a speed of 44.5 feet per minute.
has descended for 2.3 minutes

The distance the scuba diver has gone in that time is:

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Solving for distance gives us:

= 44.5 feet per minute x 2.3 minutes

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1 year ago

Cameron, Arthur, and Jamie are playing soccer. Their locations are recorded by a motion tracking system. The grid shows distanc

Luden [163]

Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{2500+400}$

$\text{Distance between Cameron and Arthur}=\sqrt{2900}$

$\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54$

Therefore, the distance Arthur is about 54 meters away from Cameron.

2. Let us find the distance between Cameron and Jamie.

$\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{625+2500}$

$\text{Distance between Cameron and Jamie}=\sqrt{3125}$

$\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56$

Therefore, Jamie is about 56 meters away from Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.

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2 years ago

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If one inch represents 18 feet, what dimensions would you use to make a scale drawing of a building 630 feet by 450 feet?

Nat2105 [25]

Answer:

35 by 25 inches

Step-by-step explanation:

1 inch = 18 feet

each 18 feet in the scale model is one inch, which means that there is one inch per 18 feet, so all you need to do is divide 630 by 18 and 450 by 18.

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2 years ago