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kompoz [17]
2 years ago
6

If one inch represents 18 feet, what dimensions would you use to make a scale drawing of a building 630 feet by 450 feet?​

Mathematics
1 answer:
Nat2105 [25]2 years ago
7 0

Answer:

35 by 25 inches

Step-by-step explanation:

1 inch = 18 feet

each 18 feet in the scale model is one inch, which means that there is one inch per 18 feet, so all you need to do is divide 630 by 18 and 450 by 18.

630/18 = 35

450/18 = 25

so the dimensions of the scale model are 35 by 25 inches

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If 2 tacos and 5 drinks cost $20, And three tacos and five drinks cost $25 how much does a taco cost
san4es73 [151]
A taco costs $5
This is because there was no difference in the cost except for $5. The only item added was one taco. Drinks cost $2 each.
4 0
2 years ago
Lakya is using the Distributive Property to divide 128 by 4. Which does not show a
Gre4nikov [31]

Answer:

Step-by-step explanation:

5 0
2 years ago
Identify the equation of the circle that has its center at (10, 24) and passes through the origin.
marishachu [46]

Answer:

A )  The Equation of the circle (x−10)2+(y−24)2=676

Step-by-step explanation:

step1:-

The equation of the circle whose center is (a,b) and radius r is

(x-a)^{2} +(y-b)^{2} =r^{2}

(x-10)^{2}+(y-24)^{2}  =676

in this circle equation centre is (g,f) = (10,24)

and formula of radius of a circle is

r = \sqrt{g^{2}+f^{2} -c }

Step2:-

The Equation of the circle (x−10)^2+(y−24)^2=676

5 0
2 years ago
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
2 years ago
A coach purchases 47 hats for his players and their families at a total cost of $302. The cost of a small hat is $5.50. A medium
frosja888 [35]

Answer:

The answer is below

Step-by-step explanation:

Let x represent the number of small hat purchased, y represent the number of medium hat purchased and z represent the number of large hat purchased.

Since a total of 47 hats where purchased,  hence:

x + y + z = 47    (1)

Also, he spent a total of $302, hence:

5.5x + 6y + 7z = 302     (2)

He purchases three times as many medium hats as small hats, hence:

y = 3x

-x + 3y = 0    (3)

Represent equations 1, 2 and 3 in matrix form gives:

\left[\begin{array}{ccc}1&1&1\\5.5&6&7\\-3&1&0\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}47\\302\\0\end{array}\right] \\\\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&1&1\\5.5&6&7\\-3&1&0\end{array}\right] ^{-1} \left[\begin{array}{c}47\\302\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}6\\18\\23\end{array}\right]

Therefore he purchases 6 small hats, 18 medium hats and 23 large hats

5 0
2 years ago
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