OSTEOARTHRITIS,
OSTEOARTHROSIS, or
DEGENERATIVE ARTHRITIS
Answer:
Recreation ans scenic areas for tourism.
Explanation:
- As the ecosystem provides a certain amount of services as habitat, healthy soil and clean air, freshwater nutrient cycle s and human goods like culture, recreation, and health. All these are benefits that humans freely gain from the natural ecosystem either be agro, forest aquatic or grasslands, etc.
Transpiration in plants requires adhesion of water molecules to cellulose, cohesion between water molecules, evaporation of water molecules and transport through tracheids. Cohesion between water molecules is as a result of hydrogen bonds between the oxygen atom of one water molecule and a hydrogen atom of another water molecule. Transpiration involves the release of water through the leaves in pores called stomata, this serves as a method of excretion of excess water and diffused gases.
A scientific argument will be considered invalid if the evidence supporting the argument is based on independent data.
If you are only referring to a single scientist or a single study conducted on a certain topic, it means that it hasn't been researched enough for the argument to be reliable. Every scientist needs to refer to other studies and other scientists and their work if they want their arguments to be valid.
Answer:
1. heterozygous yellow and star
2. 37
3. 1/8
4. 168
5. 1/4
Explanation:
Given ,
In f1 generation a cross is made between a true breeding black star bellied sneetch mated with a true breeding yellow starless sneetch
yySS x YYss
It is taken as - Y (yellow) is dominant over y (black)
and S (star) is dominant over s (starless)
1. F1 Generation
Genotype of parents yySS X YYss
gametes - yS, yS, Ys, Ys
All 16 offspring will have genotype YySs
phenotype would be heterozygous yellow and star
2. F2 generation cross
YySs X YySs
YS Ys yS ys
YS YYSS YYSs YySS YySy
Ys YYSs YYss YySs Yyss
yS YySS YySs yySS yySs
ys YySs Yyss yySs yyss
Genotype of offspring are –
YYSS – 1
YYSs – 2
YySS – 2
YySs – 4
YYss- 1
Yyss- 2
yySS – 1
yySs- 1
yyss- 1
2. Out of 16, 2 are black star bellied sneetches . Which means only 1/8 are black star bellied sneetches
So out of 300, 37 are black star bellied sneetches
3. Only 2 out of 16 are true breeding. i.e 1/8
4. 9 out of 16 are yellow star bellied sneetches, so out of 300, 168 are yellow star bellied sneetches
5. 4 out of 16 are true breeding yellow. Thus, ¼ are true breeding
