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Alekssandra [29.7K]
2 years ago
6

Which shows the correct substitution of the values a b and c from the equation -2 equals negative X Plus x squared minus 4 into

the quadratic formula?
Mathematics
1 answer:
kondor19780726 [428]2 years ago
5 0
-2=-x+x square-4
firstly regroup the equation
x square-2x+x-2=0
x square-x-2=0
multiply the first term by the last term.(I.e x square multiply by -2=-2x square)
product of factor = -2x 1
sum of factor= -2x+1(x)= -1
x square -2x+x-2=0
open the bracket:
x(x-2)+1(x-2)=0
x=1 or x=-2
Therefore; x=-1 or x=2


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abruzzese [7]

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givens

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markup = original cost * markup percent

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6 0
2 years ago
The vertices of ΔRST are R(–1,–1), S(–1,11) and T(4,11). Which could be the side lengths of a triangle that is similar but not c
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The side lengths could be 10, 24 and 26 units.

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d=\sqrt{(11--1)^2+(-1--1)^2}
\\=\sqrt{(11+1)^2+(-1+1)^2}
\\=\sqrt{12^2+0^2}=\sqrt{144}=12

For ST:
d=\sqrt{(11-11)^2+(4--1)^2}
\\=\sqrt{0^2+(4+1)^2}=\sqrt{5^2}=\sqrt{25}=5

For TR:
d=\sqrt{(11--1)^2+(4--1)^2}
\\=\sqrt{(11+1)^2+(4+1)^2}=\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13

Our side lengths, from least to greatest, are 5, 12 and 13.

To be similar but not congruent, the side lengths must have the same ratio between corresponding sides but not be the same length.  10, 24 and 26 are all 2x the original side lengths, so this works.
5 0
2 years ago
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