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deff fn [24]
2 years ago
8

the solution to the system of equation below is (−2, −1). 2x − 3y = −1 11x − 9y = −13 when the first equation is multiplied by −

3, the sum of the two equations is equivalent to 5x = −10.
Mathematics
1 answer:
Evgen [1.6K]2 years ago
6 0
When the first equation is multiplied by -3, the sum of the two equation and any of the original equations will have the same solution as the original equations. Hence 5x = -10 and 11x - 9x = -13 will have a solution of (-2, -1).
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A plumber charges a fixed fee for coming to your house, then charges a fixed amount per hour on top of this. X= the time the job
Andreyy89

Step-by-step explanation:

 This problem expects us to model the equation for the total cost of the services of the plumber given the conditions stated.

Say the fixed amount charged for coming to your house is $10

say the fix amount charged per is $3

and the time spent to do the job is X

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Answer:

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How can you use place value and period names to read and write 324,904 in word form
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5 0
2 years ago
(07.03 MC)
garri49 [273]

Answer:

9x²y¹⁴

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A federal agency responsible for enforcing laws governing weights and measures routinely inspects package to determine whether t
german

Answer:

The calculated value |t|  = 4.493>2.567 at 0.01 level of significance with

17 degrees of freedom.

Therefore the null hypothesis is rejected.

The weight of the contents is not at least as great as that advertised on the package

Step-by-step explanation:

<u>Step:-(i)</u>

Given data a random sample of 18 containers whose packing states that the contents weigh 8 ounces was drawn.

sample size 'n' = 18

mean of the population 'μ' = 8

sample mean (x⁻) =7.91, and

sample standard deviation (S) = 0.085.

<u>Step:-(ii)</u>

Given data the weight of the contents is at least as great as that advertised on the package That is

<u>Null hypothesis : 'μ' > 8</u>

<u>Alternative hypothesis:μ' < 8</u>

<u>Level of significance α=0.01</u>

Test statistic :-

t = \frac{x^{-} -u}{\frac{S}{\sqrt{n} } }

t = \frac{7.91 -8}{\frac{0.085}{\sqrt{18} } }

t = -4.493

|t| =|-4.493| = 4.493

Degrees of freedom of t- distribution γ =n-1 = 18-1=17

The tabulated value t= 2.567 at 0.01 level of significance.

<u>Conclusion</u>:-

The calculated value |t|  = 4.493>2.567 at 0.01 level of significance with

17 degrees of freedom.

Therefore the null hypothesis is rejected.

The alternative hypothesis is accepted

The weight of the contents is not at least as great as that advertised on the package.

<u></u>

6 0
2 years ago
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