Answer:
- 6 gallons per minute.
Step-by-step explanation:
Let the function that models the quantities of water, Q (in gallons) in a pool over time, t (in minutes), is
Q = a + bt ........... (1)
Now, Q(t = 0) is given to be 50 gallons.
So, a = 50 and b denotes the rate at which the quantity of water in the pool is decreasing and it is given by the slope of equation (1).
Now, two points on the graph are (0,50) and (1,44).
So, the slope = b = 
= - 6 gallons per minute.
Therefore, the equation of this situation is given by Q = 50 - 6t, where the slope is equal to - 6 gallons per minute. (Answer)
<span><u><em>The correct answer is:</em></u>
4) y-axis, x-axis, y-axis, x-axis.
<u><em>Explanation</em></u><span><u><em>: </em></u>
Reflecting a point (x,y) across the <u>x-axis</u> will map it to (x,-y).
Reflecting a point (x,y) across the <u>y-axis</u> will map it to (-x,y).
Reflecting a point (x,y) across the line <u>y=x</u> will map it to (y, x).
We want a series of transformations that will map every point (x,y) back to (x,y). This means that everything that gets done in one transformation must be undone in another. The only one where this happens is #4.
Reflecting across the y-axis first negates the x-coordinate; (x,y) goes to (-x,y).
Reflecting this across the x-axis negates the y-coordinate; (-x,y) goes to (-x,-y).
Reflecting this point back across the y-axis negates the x-coordinate again, returning it to the original: (-x,-y) goes to (x,-y).
Reflecting this point back across the x-axis negates the y-coordinate again, returning it to the original: (x,-y) goes to (x,y).
We are back to our original point.</span></span>
Answer: X= -6
Hope it helps
Answer:
Part a) The exterior surface area is equal to 
Part b) The volume is equal to 
Part c) The volume water left in the trough will be 
Step-by-step explanation:
Part a) we know that
The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles
so
<em>Find the area of two rectangles</em>
![A=2[12*5]=120\ ft^{2}](https://tex.z-dn.net/?f=A%3D2%5B12%2A5%5D%3D120%5C%20ft%5E%7B2%7D)
<em>Find the area of two trapezoids</em>
![A=2[\frac{1}{2}(8+2)h]](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%288%2B2%29h%5D)
Applying Pythagoras theorem calculate the height h
substitute the value of h to find the area
![A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%288%2B2%29%284%29%5D%3D40%5C%20ft%5E%7B2%7D)
The exterior surface area is equal to
Part b) Find the volume
We know that
The volume is equal to
where
B is the area of the trapezoidal face
L is the length of the trough
we have
substitute
Part c)
<em>step 1</em>
Calculate the area of the trapezoid for h=2 ft (the half)
the length of the midsegment of the trapezoid is (8+2)/2=5 ft
<em>step 2</em>
Find the volume
The volume is equal to
where
B is the area of the trapezoidal face
L is the length of the trough
we have
substitute
Answer:
there is no picture. :)
Step-by-step explanation:
