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Alex_Xolod [135]
2 years ago
15

Given 1 mile ≈ 1.6 kilometers, what is the standard deviation in kilometers? (enter your answer to two decimal places.)

Mathematics
1 answer:
nignag [31]2 years ago
3 0

You recorded the weekly distance you bicycled in miles and computed the standard deviation to be s= 3.1 miles. your friend wants to know the standard deviation in kilometers. Do you need to redo all the calculations?

No need to redo all the calculations. we use the given standard deviation. We convert the given standard deviation miles into kilometers.

Given 1 mile ≈ 1.6 kilometers

So 3 miles = 1.6 * 3.1 = 4.96 kilometers

standard deviation = 4.96 kilometers.

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Vika [28.1K]
0.25 inches represents 1 mile

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Find 1 inch:
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1 inch represents 1 ÷ 0.25 miles
1 inch represents 4 miles

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Find 3.75 inches:
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1 inch represents 4 miles
3.75 inches represent 4 x 3.75 miles
3.75 inches represent 15 miles

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Find 2.25 inches:
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1 inch represents 4 miles
2.25 inches represent 4 x 2.25 miles
2.25 inches represent 9 miles

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Find Area:
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Area = Length x Width
Area = 15 x 9 
Area = 135 miles²

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Answer: 135 miles²
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6 0
2 years ago
Read 2 more answers
Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form? Y = 3 (x minus seven-halves) squared minus StartFraction 27
densk [106]

Answer: y = 2 (x minus one-half) squared minus StartFraction 27 Over 2 EndFraction

or

y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

Step-by-step explanation:

Vertex form of equation : f (x) = a(x - h)^2 + k,where (h, k) is the vertex of the parabola.

y=3(x-2)^2-(x-5)^2\\\\=3(x^2+4-4x)-(x^2+25-10x)\\\\=3x^2+12-12x-x^2-25+10x\\\\=2x^2-2x-13\\\\=2(x^2-x-\dfrac{13}{2})\\\\=2(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{13}{2})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{1+26}{4})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{27}{4})=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

Hence, the vertex form of the equation is y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

8 0
2 years ago
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guajiro [1.7K]

Answer:

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\frac{500}{5} = 100 ← value of 1 part of the ratio

The mums consisted of 3 parts, hence

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3 0
2 years ago
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dusya [7]

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Simplify by evaluating the coefficients and powers of 3.

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2 years ago
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