There are nine students in the chess club the club moderator select three of them to go to a chess tournament and how many ways
2 answers:
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First, we are going to find the sum of their age. To do that we are going to add the age of Eli, the age Freda, and the age of <span>Geoff:
</span>
The combined age of Eli, Freda, and Geoff is 40, so the denominator of each ratio will be 40.
Next, we are going to multiply the ratio between the age of the person and their combined age by <span>£800:
For Eli: </span>
For Freda:
For Geoff:
<span>
We can conclude that Eli will get </span>£180, Freda will get £260, and Geoff will get <span>£360.</span>
</span>
The combined age of Eli, Freda, and Geoff is 40, so the denominator of each ratio will be 40.
Next, we are going to multiply the ratio between the age of the person and their combined age by <span>£800:
For Eli: </span>
For Freda:
For Geoff:
<span>
We can conclude that Eli will get </span>£180, Freda will get £260, and Geoff will get <span>£360.</span>
