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2 years ago

13

If 5^3b-3 what is the value of b

1 answer:

Alisiya [41]2 years ago

5 0

To do this problem, take your answer options and one-by-one replace b with the options. Once it can total out to be an absolute number, then it is correct. Happy to work it out with you if you can't figure it out !

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After 8 years a loan grows to $75 210. If the interest was compounded annually at a rate of 8.5%, find the size of the initial l

stealth61 [152]

Given:
Future Value = $75,210
term = 8 years
rate = 8.5%
Initial loan = ?

In this case, we need to find the present value of the loan. Compounded means that even the interest has an interest.

PV = FV / (1 + i)^n

PV = 75,210 / (1 + 0.085)⁸

PV = 75,210 / (1.085)⁸

PV = 75,210 / 1.9206

PV = 39,159.64

Initial loan is $39,159.64
total interest is $75,210 - 39,159.64 = $36,050.36

3 0

2 years ago

Question and answer choices are in the screenshot. THANK YOU!!

Anika [276]

I 11 x - 22 I > 22
∴ 11x-22 > 22          OR          (11x -22) < -22
∴ 11 x > 44             ::::::::          11x - 22 < -22
    x > 4                   ::::::::              x < 0

∴ x ∈ ( -∞ , 0 ) ∪ ( 4 , ∞)
∴ The correct choice is number 1
The solution is attached in the figure

5 0

2 years ago

7. You and a friend are paid $38.25 for doing yard

nata0808 [166]

Answer:

Step-by-step explanation: your friend would get 17$

and you would get 21.25

hope this helpsss ;))))

8 0

2 years ago

Read 2 more answers

The product of a binomial and a trinomial is x 3 + 3 x 2 − x + 2 x 2 + 6 x − 2. Which expression is equivalent to this product a

Mazyrski [523]

X3+5x2+5×-2 is the correct answer.

4 0

2 years ago

Read 2 more answers

The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.

Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

$h(t)=-16t^2+80t+64$

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A) Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

$-16t^2+80t+64=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+80t+64=0$

so

$a=-16\\b=80\\c=64$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{10,496}} {-32}$

$t=\frac{-80+\sqrt{10,496}} {-32}=-0.70$

$t=\frac{-80-\sqrt{10,496}} {-32}=5.70$

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

$-16t^2+80t+64=40$

$-16t^2+80t+24=0$

Solve the quadratic equation

we have

$a=-16\\b=80\\c=24$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{7,936}} {-32}$

$t=\frac{-80+\sqrt{7,936}} {-32}=-0.28$

$t=\frac{-80-\sqrt{7,936}} {-32}=5.28$

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0

2 years ago