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AfilCa [17]
2 years ago
14

if a boy grows 5 inches, he will be one-half as tall as his sister. His sister is 68 inches tall. How tall is the boy?

Mathematics
2 answers:
elena-14-01-66 [18.8K]2 years ago
7 0

If the boy grows another 5 inches, he will be 1/2 as tall as his sister. HIs sister is 68 inch tall

Let sister = g, and boy = b

2b + 5 = g

g = 68

Plug in 68 for g

2b + 5 = 68

Isolate the b. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

first, subtract 5 from both sdies

2b + 5 (-5) = 68 (-5)

2b = 68 - 5

2b = 63

Isolate the b. Divide 2 from both sides

2b/2 = 63/2

b = 63/2

b = 31.5

The boy is 31.5 inches tall

hope this helps

IRINA_888 [86]2 years ago
6 0

Answer:

The height of boy is 29 inches.

Step-by-step explanation:

Given : If a boy grows 5 inches, he will be one-half as tall as his sister. His sister is 68 inches tall.

To find : How tall is the boy?  

Solution :

Let x be the boy's height and y be his sister's height.

We have given, His sister is 68 inches tall i.e. y=68 inches

Now,  If a boy grows 5 inches i.e. x+5

then he will be one-half as tall as his sister i.e. x+5=\frac{1}{2}y

or  y=2x+10

We know, y=68 substitute in above equation

68=2x+10

2x=58

x=\frac{58}{2}

x=29

Therefore, The height of boy is 29 inches.

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Step-by-step explanation:

The following information is given in the question

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2 years ago
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In professional basketball games during 2009-2010, when Kobe Bryant of the Los Angeles Lakers shot a pair of free throws, 8 time
ziro4ka [17]

Answer:

Is plausible that the successive throws are independent

Step-by-step explanation:

1) Table with info given

The observed values are given by the following table

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First shot          Made          Second shot missed           Total

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Made                  152                       33                                185

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We are interested on check independence and for this we need to conduct a chi square test, the next step would be find the expected value:

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Made                  189(185)/230=152.0217                41(185)/230=32.9783

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_____________________________________________________

On this case all the expected values are higher than 5 and the sample size 230 is enough to apply the chi squared test.

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The statistic for this case is given by:

\chi_{cal}^2 =\sum \frac{(O_i -E_i)}{E_i}

Where O represent the observed values and E the expected values. Replacing the values that we got we have this

\chi_{cal}^2 =\frac{(152-152.0217)^2}{152.0217}+\frac{(33-32.9783)^2}{32.9783}+\frac{(37-36.9783)^2}{36.9783}+\frac{(8-8.0217)^2}{8.0217}=0.000003098+0.00001428+0.00001273+0.0.00005870=0.00008881

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