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ivolga24 [154]
2 years ago
3

In a shipment of 80 vials, only 13 do not have hairline cracks. if you randomly select 3 vials from the shipment, what is the pr

obability that all 3 of the selected vials have hairline cracks?
Mathematics
1 answer:
allochka39001 [22]2 years ago
3 0

The probability that all 3 of the selected vials have hairline cracks will be 0.583....

<u><em>Explanation</em></u>

Total number of vials is 80 and 13 do not have hairline cracks.

So, the number of vials that have hairline cracks = 80-13 = 67

We need to randomly select 3 vials from the shipment. So, the total possible ways for selecting 3 vials from 80 will be: ^8^0C_{3}

Now, the number of ways for selecting 3 vials from 67 that have hairline cracks = ^6^7C_{3}

So, the probability = \frac{^6^7C_{3}}{^8^0C_{3}}=0.583.....

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Answer:

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Step-by-step explanation:

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To do so, we need to use the quadratic formula, which states that the solution to any equation of the form ax^2 + bx + c = 0 is:

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So, the first thing we're going to do is divide the whole function by 6:

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This step is optional, but it makes things quite easier.

Then we using the quadratic formula, where:

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Then:

x=\frac{-2±\sqrt{2^{2}-4(1)(-7/6)}}{2}

x=\frac{-2±\sqrt{4 +14/3}}{2}

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So the zeros are:

x1=\frac{-2+\sqrt{26/3}}{2}

x2=\frac{-2-\sqrt{26/3}}{2}

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2 years ago
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