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Tpy6a [65]
2 years ago
12

Adam wraps the top edge of the gift box shown with gold ribbon. The top and bottom edges of the box are square. If Adam has 24 1

/4 cm of gold ribbon, does he have enough to decorate the top of the box?
Mathematics
1 answer:
Marysya12 [62]2 years ago
3 0

No , he does not have enough

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A 3-column table with 4 rows. Column 1 has entries Computer repair, sales tax, gratuity, shipping. Column 2 is labeled Store A w
SVETLANKA909090 [29]

Answer:

A

Step-by-step explanation:

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arah mailed her computer to Store B for repairs. Her bill was: Total Cost of Computer Repair = $1,444.50 Shipping = 2 percent of
nataly862011 [7]
1415.61 IS HER TOTAL BILL BEFORE SHIPPING. 1415.61X .15=212.34 

1415.61 REPAIR
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If henry were to add 5 gallons of water to a tank that is already 34 full of water, the tank would be 78 full. how many gallons
taurus [48]
Please express those fractions properly:  3/4, 7/8.

Let g be the # of gallons the tank could hold when full.  

Then (3/4)n + 5 = (7/8)n.  

solving for n:  Mult all 3 terms by the LCD (8):  6n + 5(8) = 7n.

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5 0
2 years ago
*please help, will thank*
Wittaler [7]
I think the answer is (d) appraisal fee. Hope this helps!
7 0
2 years ago
New Clarendon Park is undergoing renovations to its gardens. One garden that was originally a square is being adjusted so that o
frosja888 [35]
The answer is 80 square meters.

The square area is expressed as:
A = a²,
where A is the area of the square, and a is the side of the square.

The rectangle area is expressed as:
A₁ = a₁ · b₁,
where A₁ is the area of the rectangle, and a₁ and b₁ are the sides of the rectangle.

After renovations, square garden becomes rectangular.

One side is doubled in length:
a₁ = 2a

The other side is decreased by three meters.
b₁ = a - 3

The new area is 25% than the original square garden:
A₁ = A + 25%A =
     = A + 25/100·A
     = A + 1/25·A
     = a² + 1/25·a²
     = <span>a² + 0.25·a²
</span>     = 1.25·a²

If the starting equation is:
A₁ = a₁ · b₁

Thus, the equation is:
1.25a² = 2a·(<span>a - 3)
</span>1.25a² = 2a · a - 2a · 3
1.25a² = 2a² - 6a

<span>Therefore, the equation that could be used to determine the length of a side of the original square garden is:
</span><u>2a² - 6a = </u><span><u>1.25a²</u></span>


Now, we will solve the equation:
2a² - 6a = 1.25a²
2a² - 1.25a² - 6a = 0
0.75a² - 6a = 0
⇒ a(0.75a - 6) = 0

From here, one of the multiplier must be zero - either a or (0.75a - 6). Since a could not be zero, (0.75a - 6) is:
0.75a - 6 = 0
0.75a = 6
a = 6 ÷ 0.75
a = 8

If the side of the square is 8, then the area of the rectangle is
A₁ = 1.25 · a²
A₁ = 1.25 ·8²
A₁ = 1.25 · 64
A₁ = 80

Therefore, the area of the new rectangle garden is 80 square meters.
4 0
3 years ago
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